CAIE S1 2014 June — Question 6 10 marks

Exam BoardCAIE
ModuleS1 (Statistics 1)
Year2014
SessionJune
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPermutations & Arrangements
TypeArrangements with alternating patterns
DifficultyModerate -0.3 This is a straightforward permutations and combinations question testing standard techniques: treating grouped letters as single units, counting arrangements with restrictions, and basic selection problems. Part (ii) requires careful counting of alternating patterns but follows a mechanical approach. All parts are routine applications of A-level methods with no novel insight required, making it slightly easier than average.
Spec5.01a Permutations and combinations: evaluate probabilities5.01b Selection/arrangement: probability problems

6 Find the number of different ways in which all 8 letters of the word TANZANIA can be arranged so that
  1. all the letters A are together,
  2. the first letter is a consonant ( \(\mathrm { T } , \mathrm { N } , \mathrm { Z }\) ), the second letter is a vowel ( \(\mathrm { A } , \mathrm { I }\) ), the third letter is a consonant, the fourth letter is a vowel, and so on alternately. 4 of the 8 letters of the word TANZANIA are selected. How many possible selections contain
  3. exactly 1 N and 1 A ,
  4. exactly 1 N ?

AnswerMarks Guidance
(i) \(\frac{6!}{2!} = 360\)B1 6! Seen alone
B12 Dividing by 2! only
(ii) \(\frac{4!}{2!} \times \frac{4!}{3!}\)B1 4! seen mult
B1Dividing by 2! or 3! (Mult by 4 implied B1B1)
\(= 48\)B1 3
(iii) 1N and 1A: N A xx in \(^3C_2\) = 3 waysM1 \(^3C_x\) or \(^2C_x\) seen alone
A12 Correct answer
(iv) 0 A : Nxxx = 1 wayM1 Finding ways with 0 or 2 or 3 As
2 As: NAAx in \(^3C_1\) = 3 waysM1 Summing 3 or 4 options
3 As: NAAA in 1 way
Total = 8 waysA1 3
(i) $\frac{6!}{2!} = 360$ | B1 | 6! Seen alone
| B1 | 2 | Dividing by 2! only

(ii) $\frac{4!}{2!} \times \frac{4!}{3!}$ | B1 | 4! seen mult
| B1 | Dividing by 2! or 3! (Mult by 4 implied B1B1)
$= 48$ | B1 | 3 | Correct answer

(iii) 1N and 1A: N A xx in $^3C_2$ = 3 ways | M1 | $^3C_x$ or $^2C_x$ seen alone
| A1 | 2 | Correct answer

(iv) 0 A : Nxxx = 1 way | M1 | Finding ways with 0 or 2 or 3 As
2 As: NAAx in $^3C_1$ = 3 ways | M1 | Summing 3 or 4 options
3 As: NAAA in 1 way | | 
Total = 8 ways | A1 | 3 | Correct answer
6 Find the number of different ways in which all 8 letters of the word TANZANIA can be arranged so that\\
(i) all the letters A are together,\\
(ii) the first letter is a consonant ( $\mathrm { T } , \mathrm { N } , \mathrm { Z }$ ), the second letter is a vowel ( $\mathrm { A } , \mathrm { I }$ ), the third letter is a consonant, the fourth letter is a vowel, and so on alternately.

4 of the 8 letters of the word TANZANIA are selected. How many possible selections contain\\
(iii) exactly 1 N and 1 A ,\\
(iv) exactly 1 N ?

\hfill \mbox{\textit{CAIE S1 2014 Q6 [10]}}