CAIE S1 2014 June — Question 4 7 marks

Exam BoardCAIE
ModuleS1 (Statistics 1)
Year2014
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHypergeometric Distribution
TypeCalculate variance given expectation
DifficultyStandard +0.3 This is a straightforward hypergeometric distribution question requiring standard probability calculations and variance formula application. Part (i) is routine verification, part (ii) involves computing 3-4 probabilities using combinations, and part (iii) requires calculating E(X²) from the distribution table then using Var(X) = E(X²) - [E(X)]². All steps are mechanical applications of standard S1 techniques with no conceptual challenges or novel insights required.
Spec2.04a Discrete probability distributions5.02a Discrete probability distributions: general5.02b Expectation and variance: discrete random variables

4 A book club sends 6 paperback and 2 hardback books to Mrs Hunt. She chooses 4 of these books at random to take with her on holiday. The random variable \(X\) represents the number of paperback books she chooses.
  1. Show that the probability that she chooses exactly 2 paperback books is \(\frac { 3 } { 14 }\).
  2. Draw up the probability distribution table for \(X\).
  3. You are given that \(\mathrm { E } ( X ) = 3\). Find \(\operatorname { Var } ( X )\).

AnswerMarks Guidance
(i) \(P(\text{exactly 2}) = \frac{^6C_2}{^8C_4} = \frac{15}{70} = \frac{3}{14}\) AGM1 \(^6C_x / ^8C_x\) seen or \(^6C_2\) mult by 4 fractions (last 2 can be implied)
OR \(P(2) = \frac{6}{8} \times \frac{5}{7} \times \frac{2}{6} \times \frac{1}{5} \times ^4C_2 = \frac{3}{14}\) AGA1 2
(ii)\(x\) 2
Prob3/14 8/14
B1one correct prob other than P(2)
B1♦3 third correct prob if \(\sum = 1\)
(iii) \(\text{Var}(X) = \frac{12}{14} + \frac{72}{14} + \frac{48}{14} - 3^2\)M1 using \(\sum x^2 p - 3^2\) (or their {\(E(X)\)}\(^2\)) must be evaluated
\(= \frac{3}{7}\) (0.429)A1 2
(i) $P(\text{exactly 2}) = \frac{^6C_2}{^8C_4} = \frac{15}{70} = \frac{3}{14}$ AG | M1 | $^6C_x / ^8C_x$ seen or $^6C_2$ mult by 4 fractions (last 2 can be implied)

OR $P(2) = \frac{6}{8} \times \frac{5}{7} \times \frac{2}{6} \times \frac{1}{5} \times ^4C_2 = \frac{3}{14}$ AG | A1 | 2 | Answer legit obtained

(ii) | $x$ | 2 | 3 | 4 |
| Prob | 3/14 | 8/14 | 3/14 | | B1 | 2, 3, 4 only in top line
| | | | | B1 | one correct prob other than P(2)
| | | | | B1♦ | 3 | third correct prob if $\sum = 1$

(iii) $\text{Var}(X) = \frac{12}{14} + \frac{72}{14} + \frac{48}{14} - 3^2$ | M1 | using $\sum x^2 p - 3^2$ (or their {$E(X)$}$^2$) must be evaluated
$= \frac{3}{7}$ (0.429) | A1 | 2 | correct answer
4 A book club sends 6 paperback and 2 hardback books to Mrs Hunt. She chooses 4 of these books at random to take with her on holiday. The random variable $X$ represents the number of paperback books she chooses.\\
(i) Show that the probability that she chooses exactly 2 paperback books is $\frac { 3 } { 14 }$.\\
(ii) Draw up the probability distribution table for $X$.\\
(iii) You are given that $\mathrm { E } ( X ) = 3$. Find $\operatorname { Var } ( X )$.

\hfill \mbox{\textit{CAIE S1 2014 Q4 [7]}}