CAIE S1 2013 June — Question 2 4 marks

Exam BoardCAIE
ModuleS1 (Statistics 1)
Year2013
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMeasures of Location and Spread
TypeCalculate variance/SD from coded sums
DifficultyModerate -0.8 This is a straightforward application of standard variance formulas using coded data. Students need to recall the formula for variance from coded sums (Var(x) = Σ(x-a)²/n - [Σ(x-a)/n]²) and then use Σx² = Σ(x-50)² + 100Σ(x-50) + 2500n. Both are direct formula applications with no problem-solving or conceptual insight required, making this easier than average.
Spec2.02g Calculate mean and standard deviation

2 A summary of the speeds, \(x\) kilometres per hour, of 22 cars passing a certain point gave the following information: $$\Sigma ( x - 50 ) = 81.4 \quad \text { and } \quad \Sigma ( x - 50 ) ^ { 2 } = 671.0 .$$ Find the variance of the speeds and hence find the value of \(\Sigma x ^ { 2 }\).

Question 2:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\bar{x} = 50 + 81.4/22 = 53.7\)M1 Attempt to find variance using coding in both, correct formula
\(\text{var} = 671/22 - 3.7^2 = 16.81\ (16.8)\)A1 Correct answer using their var and their mean with uncoded formula for both
\(16.81 = \Sigma x^2/22 - 53.7^2\)M1
\(= 63811\ (63800)\)A1 [4] Correct answer
OR
\(\Sigma x - 22\times50 = 81.4\ (\Sigma x = 1181.4)\)M1 Expanded eqn with \(22\times50\) seen
\(\Sigma x^2 - 100\Sigma x + 22\times50^2 = 671\)M1 Expanded eqn with 2 or 3 terms correct
\(\Sigma x^2 = 671 + 118140 - 55000 = 63811\)A1 Correct answer
\(\text{Var} = \Sigma x^2/22 - (\Sigma x/22)^2 = 16.81\)A1 Correct answer
## Question 2:

| Answer/Working | Marks | Guidance |
|---|---|---|
| $\bar{x} = 50 + 81.4/22 = 53.7$ | M1 | Attempt to find variance using coding in both, correct formula |
| $\text{var} = 671/22 - 3.7^2 = 16.81\ (16.8)$ | A1 | Correct answer using their var and their mean with uncoded formula for both |
| $16.81 = \Sigma x^2/22 - 53.7^2$ | M1 | |
| $= 63811\ (63800)$ | A1 **[4]** | Correct answer |
| **OR** | | |
| $\Sigma x - 22\times50 = 81.4\ (\Sigma x = 1181.4)$ | M1 | Expanded eqn with $22\times50$ seen |
| $\Sigma x^2 - 100\Sigma x + 22\times50^2 = 671$ | M1 | Expanded eqn with 2 or 3 terms correct |
| $\Sigma x^2 = 671 + 118140 - 55000 = 63811$ | A1 | Correct answer |
| $\text{Var} = \Sigma x^2/22 - (\Sigma x/22)^2 = 16.81$ | A1 | Correct answer |

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2 A summary of the speeds, $x$ kilometres per hour, of 22 cars passing a certain point gave the following information:

$$\Sigma ( x - 50 ) = 81.4 \quad \text { and } \quad \Sigma ( x - 50 ) ^ { 2 } = 671.0 .$$

Find the variance of the speeds and hence find the value of $\Sigma x ^ { 2 }$.

\hfill \mbox{\textit{CAIE S1 2013 Q2 [4]}}