Standard +0.3 This is a straightforward normal distribution problem requiring standardization and inverse normal lookup. The linear relationship μ = 5σ reduces it to one unknown, and the calculation is routine once set up: (20-5σ)/σ = 1.45 from tables, giving σ = 4 and μ = 20. Slightly above average difficulty due to the algebraic setup with the constraint, but still a standard S1 exercise.
1 The random variable \(Y\) is normally distributed with mean equal to five times the standard deviation. It is given that \(\mathrm { P } ( Y > 20 ) = 0.0732\). Find the mean.
1 The random variable $Y$ is normally distributed with mean equal to five times the standard deviation. It is given that $\mathrm { P } ( Y > 20 ) = 0.0732$. Find the mean.
\hfill \mbox{\textit{CAIE S1 2013 Q1 [3]}}