CAIE S1 2007 June — Question 5 7 marks

Exam BoardCAIE
ModuleS1 (Statistics 1)
Year2007
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPermutations & Arrangements
TypeArrangements with adjacency requirements
DifficultyModerate -0.3 This is a standard permutations question testing arrangements with repeated letters and basic selection. Part (i)(a) is direct application of n!/n₁!n₂!... formula, (i)(b) requires the standard 'treat as one unit' technique, and (ii) combines selection with restrictions. All techniques are routine for S1 level with no novel problem-solving required, making it slightly easier than average.
Spec5.01a Permutations and combinations: evaluate probabilities5.01b Selection/arrangement: probability problems

5
  1. Find the number of ways in which all twelve letters of the word REFRIGERATOR can be arranged
    1. if there are no restrictions,
    2. if the Rs must all be together.
    3. How many different selections of four letters from the twelve letters of the word REFRIGERATOR contain no Rs and two Es?

Question 5:
Part (i)(a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\dfrac{12!}{4!\,2!} = 9979200\) (9980000)B1 Dividing by \(4!\) and \(2!\) only
B1 2Correct answer
Part (i)(b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\dfrac{9!}{2!} = 181440\) (181000)B1 \(9!\) or \(9 \times 8!\) seen not in denom
B1 2Correct answer
Part (ii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(_{6}C_2\) or \(_{4}C_0 \times {}_{2}C_2 \times {}_{6}C_2\) or \(_{6}C_4\) or \(_{6}P_2/2!\)M1 For seeing \({}_{6}C_{\text{something}}\) or \({}_{6}P_{\text{something}}\) in a product (could be with 1)
M1For seeing \({}_{\text{something}}C_2\) or \({}_{6}C_4\)
\(= 15\)A1 3 Correct answer; 15 with no working scores full marks
## Question 5:

### Part (i)(a):
| Answer/Working | Mark | Guidance |
|---|---|---|
| $\dfrac{12!}{4!\,2!} = 9979200$ (9980000) | B1 | Dividing by $4!$ and $2!$ only |
| | B1 **2** | Correct answer |

### Part (i)(b):
| Answer/Working | Mark | Guidance |
|---|---|---|
| $\dfrac{9!}{2!} = 181440$ (181000) | B1 | $9!$ or $9 \times 8!$ seen not in denom |
| | B1 **2** | Correct answer |

### Part (ii):
| Answer/Working | Mark | Guidance |
|---|---|---|
| $_{6}C_2$ or $_{4}C_0 \times {}_{2}C_2 \times {}_{6}C_2$ or $_{6}C_4$ or $_{6}P_2/2!$ | M1 | For seeing ${}_{6}C_{\text{something}}$ or ${}_{6}P_{\text{something}}$ in a product (could be with 1) |
| | M1 | For seeing ${}_{\text{something}}C_2$ or ${}_{6}C_4$ |
| $= 15$ | A1 **3** | Correct answer; 15 with no working scores full marks |

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5 (i) Find the number of ways in which all twelve letters of the word REFRIGERATOR can be arranged
\begin{enumerate}[label=(\alph*)]
\item if there are no restrictions,
\item if the Rs must all be together.\\
(ii) How many different selections of four letters from the twelve letters of the word REFRIGERATOR contain no Rs and two Es?
\end{enumerate}

\hfill \mbox{\textit{CAIE S1 2007 Q5 [7]}}