CAIE S1 2007 June — Question 3 7 marks

Exam BoardCAIE
ModuleS1 (Statistics 1)
Year2007
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNormal Distribution
TypeLinear relationship μ = kσ
DifficultyStandard +0.3 Part (a) requires setting up μ=2σ, standardizing to find z-score from tables (z≈-1.28), then solving a linear equation—straightforward application of normal distribution with one extra algebraic step. Part (b) is direct recall that P(μ-σ < X < μ+σ) ≈ 0.68, multiplied by 800. Both parts are routine S1 exercises requiring standard techniques without problem-solving insight.
Spec2.04e Normal distribution: as model N(mu, sigma^2)2.04f Find normal probabilities: Z transformation

3
  1. The random variable \(X\) is normally distributed. The mean is twice the standard deviation. It is given that \(\mathrm { P } ( X > 5.2 ) = 0.9\). Find the standard deviation.
  2. A normal distribution has mean \(\mu\) and standard deviation \(\sigma\). If 800 observations are taken from this distribution, how many would you expect to be between \(\mu - \sigma\) and \(\mu + \sigma\) ?

Question 3:
Part (a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\dfrac{5.2 - 2s}{s} = -1.282\)M1 Equation with \(\pm\) correct LHS seen here or later, can be \(\mu\) or \(s\), no cc
B1\(\pm 1.282\) seen, accept \(\pm 1.28\) or anything in between
M1Solving their equation with recognisable \(z\)-value and only 1 unknown occurring twice
\(s = 7.24\) or \(7.23\)A1 4 Correct final answer
Part (b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\Phi\!\left(\dfrac{\mu + \sigma - \mu}{\sigma}\right) = 0.8413\)B1 \(0.8413\) (p) seen or implied (can use their own numbers)
\(P(\lvert z \rvert < 1) = 0.3413 \times 2 = 0.6826\)M1 Finding the correct area i.e. \(2p - 1\)
\(0.6826 \times 800 = 546\) (accept 547)A1 3 Correct answer, must be a positive integer
OR \(SR\ 800 \times 2/3 = 533\) or \(534\)SR B1 for \(2/3\)
B1for 533 or 534 or B2 if 533 or 534 and no working
## Question 3:

### Part (a):
| Answer/Working | Mark | Guidance |
|---|---|---|
| $\dfrac{5.2 - 2s}{s} = -1.282$ | M1 | Equation with $\pm$ correct LHS seen here or later, can be $\mu$ or $s$, no cc |
| | B1 | $\pm 1.282$ seen, accept $\pm 1.28$ or anything in between |
| | M1 | Solving their equation with recognisable $z$-value and only 1 unknown occurring twice |
| $s = 7.24$ or $7.23$ | A1 **4** | Correct final answer |

### Part (b):
| Answer/Working | Mark | Guidance |
|---|---|---|
| $\Phi\!\left(\dfrac{\mu + \sigma - \mu}{\sigma}\right) = 0.8413$ | B1 | $0.8413$ (p) seen or implied (can use their own numbers) |
| $P(\lvert z \rvert < 1) = 0.3413 \times 2 = 0.6826$ | M1 | Finding the correct area i.e. $2p - 1$ |
| $0.6826 \times 800 = 546$ (accept 547) | A1 **3** | Correct answer, must be a positive integer |
| OR $SR\ 800 \times 2/3 = 533$ or $534$ | SR B1 | for $2/3$ |
| | B1 | for 533 or 534 or B2 if 533 or 534 and no working |

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3
\begin{enumerate}[label=(\alph*)]
\item The random variable $X$ is normally distributed. The mean is twice the standard deviation. It is given that $\mathrm { P } ( X > 5.2 ) = 0.9$. Find the standard deviation.
\item A normal distribution has mean $\mu$ and standard deviation $\sigma$. If 800 observations are taken from this distribution, how many would you expect to be between $\mu - \sigma$ and $\mu + \sigma$ ?
\end{enumerate}

\hfill \mbox{\textit{CAIE S1 2007 Q3 [7]}}