CAIE S1 2021 November — Question 2 4 marks

Exam BoardCAIE
ModuleS1 (Statistics 1)
Year2021
SessionNovember
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMeasures of Location and Spread
TypeCalculate mean from coded sums
DifficultyModerate -0.8 This is a straightforward application of coding formulas for mean and variance. Part (a) requires simple algebraic manipulation of Σ(x-k)/n = x̄ - k, and part (b) uses the standard variance formula with coded data. Both are direct recall of standard results with minimal problem-solving required, making it easier than average.
Spec2.02f Measures of average and spread2.02g Calculate mean and standard deviation

2 A summary of 40 values of \(x\) gives the following information: $$\Sigma ( x - k ) = 520 , \quad \Sigma ( x - k ) ^ { 2 } = 9640$$ where \(k\) is a constant.
  1. Given that the mean of these 40 values of \(x\) is 34 , find the value of \(k\).
  2. Find the variance of these 40 values of \(x\).

Question 2:
Part 2(a):
\(\left[\frac{\sum x}{40} - k = \frac{\sum(x-k)}{40}\right]\)
AnswerMarks Guidance
\(\frac{40 \times 34}{40} - k = \frac{520}{40}\)M1 Forms an equation involving \(\Sigma x\), \(\Sigma(x-k)\) and \(k\). Accept at a numeric stage with \(k\).
\(k\ [= 34 - 13] = 21\)A1 Evaluated.

Total: 2 marks

Question 2(b):
AnswerMarks Guidance
AnswerMarks Guidance
\(\text{Var} = \left[\frac{\sum(x-k)^2}{40} - \left(\frac{\sum(x-k)}{40}\right)^2\right] = \frac{9640}{40} - \left(\frac{520}{40}\right)^2 = [241 - 13^2 =]\)M1 Values substituted into an appropriate variance formula, accept unsimplified
\(72\)A1
**Question 2:**

**Part 2(a):**

$\left[\frac{\sum x}{40} - k = \frac{\sum(x-k)}{40}\right]$

$\frac{40 \times 34}{40} - k = \frac{520}{40}$ | M1 | Forms an equation involving $\Sigma x$, $\Sigma(x-k)$ and $k$. Accept at a numeric stage with $k$.

$k\ [= 34 - 13] = 21$ | A1 | Evaluated.

Total: **2 marks**

## Question 2(b):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\text{Var} = \left[\frac{\sum(x-k)^2}{40} - \left(\frac{\sum(x-k)}{40}\right)^2\right] = \frac{9640}{40} - \left(\frac{520}{40}\right)^2 = [241 - 13^2 =]$ | M1 | Values substituted into an appropriate variance formula, accept unsimplified |
| $72$ | A1 | |

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2 A summary of 40 values of $x$ gives the following information:

$$\Sigma ( x - k ) = 520 , \quad \Sigma ( x - k ) ^ { 2 } = 9640$$

where $k$ is a constant.
\begin{enumerate}[label=(\alph*)]
\item Given that the mean of these 40 values of $x$ is 34 , find the value of $k$.
\item Find the variance of these 40 values of $x$.
\end{enumerate}

\hfill \mbox{\textit{CAIE S1 2021 Q2 [4]}}