CAIE S1 2021 June — Question 1 5 marks

Exam BoardCAIE
ModuleS1 (Statistics 1)
Year2021
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMeasures of Location and Spread
TypeDirect cumulative frequency graph reading
DifficultyEasy -1.8 This question requires only direct reading of values from a cumulative frequency graph with no calculations or interpretation beyond basic percentile concepts. All three parts involve straightforward graph reading: (a) read y-value at x=100, (b) find x-value at y=104 (65% of 160), (c) find Q3-Q1. This is purely mechanical with no problem-solving element, making it significantly easier than average A-level questions.
Spec2.02a Interpret single variable data: tables and diagrams

1 The heights in cm of 160 sunflower plants were measured. The results are summarised on the following cumulative frequency curve. \includegraphics[max width=\textwidth, alt={}, center]{b72bd3eb-2c10-4d01-ab18-74d6fb812f27-02_1783_1424_404_356}
  1. Use the graph to estimate the number of plants with heights less than 100 cm .
  2. Use the graph to estimate the 65th percentile of the distribution.
  3. Use the graph to estimate the interquartile range of the heights of these plants.

Question 1:
Part (a):
AnswerMarks Guidance
AnswerMarks Guidance
\(60\)B1 Accept 60 or 61. No decimals
Total: 1
Part (b):
AnswerMarks Guidance
AnswerMarks Guidance
\(65\%\) of \(160 = 104\)M1 \(0.65 \times 160\ (=104)\) seen unsimplified or implied by use on graph
\(136\) (cm)A1 Use of graph must be seen. SCB1 correct value (136 only) if neither 104 nor use of graph are evident
Total: 2
Part (c):
AnswerMarks Guidance
AnswerMarks Guidance
UQ: \(150\), LQ: \(76\)M1 \(UQ - LQ\); \(148 \leqslant UQ \leqslant 152\); \(74 \leqslant LQ \leqslant 78\)
\(IQR = 150 - 76 = 74\) [cm]A1 Must be from \(150 - 76\)
Total: 2
**Question 1:**

**Part (a):**

| Answer | Marks | Guidance |
|--------|-------|----------|
| $60$ | B1 | Accept 60 or 61. No decimals |
| | **Total: 1** | |

---

**Part (b):**

| Answer | Marks | Guidance |
|--------|-------|----------|
| $65\%$ of $160 = 104$ | M1 | $0.65 \times 160\ (=104)$ seen unsimplified or implied by use on graph |
| $136$ (cm) | A1 | Use of graph must be seen. **SCB1** correct value (136 only) if neither 104 nor use of graph are evident |
| | **Total: 2** | |

---

**Part (c):**

| Answer | Marks | Guidance |
|--------|-------|----------|
| UQ: $150$, LQ: $76$ | M1 | $UQ - LQ$; $148 \leqslant UQ \leqslant 152$; $74 \leqslant LQ \leqslant 78$ |
| $IQR = 150 - 76 = 74$ [cm] | A1 | Must be from $150 - 76$ |
| | **Total: 2** | |
1 The heights in cm of 160 sunflower plants were measured. The results are summarised on the following cumulative frequency curve.\\
\includegraphics[max width=\textwidth, alt={}, center]{b72bd3eb-2c10-4d01-ab18-74d6fb812f27-02_1783_1424_404_356}
\begin{enumerate}[label=(\alph*)]
\item Use the graph to estimate the number of plants with heights less than 100 cm .
\item Use the graph to estimate the 65th percentile of the distribution.
\item Use the graph to estimate the interquartile range of the heights of these plants.
\end{enumerate}

\hfill \mbox{\textit{CAIE S1 2021 Q1 [5]}}