CAIE P1 2014 June — Question 8 8 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2014
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicInequalities
TypeComplete the square technique
DifficultyModerate -0.8 This is a straightforward completing the square exercise followed by a standard discriminant application. Part (i) is routine algebraic manipulation with a direct read-off of the minimum value. Part (ii) requires rearranging to standard form and applying b²-4ac < 0, which is a standard technique taught early in P1. The question is easier than average as it involves well-practiced procedures with no problem-solving insight required.
Spec1.02d Quadratic functions: graphs and discriminant conditions1.02e Complete the square: quadratic polynomials and turning points1.02g Inequalities: linear and quadratic in single variable

8
  1. Express \(2 x ^ { 2 } - 10 x + 8\) in the form \(a ( x + b ) ^ { 2 } + c\), where \(a , b\) and \(c\) are constants, and use your answer to state the minimum value of \(2 x ^ { 2 } - 10 x + 8\).
  2. Find the set of values of \(k\) for which the equation \(2 x ^ { 2 } - 10 x + 8 = k x\) has no real roots.

AnswerMarks Guidance
\(2x^2 - 10x + 8 \rightarrow a(x+b)^2 + c\)
(i) \(a = 2, b = -\frac{1}{2}, c = -4\frac{1}{2}\)3 × B1 Or \(2\left[x - 2\frac{1}{2}\right]^2 - 4\frac{1}{2}\)
\(\rightarrow\) min value is \(-4\frac{1}{2}\) Allow \(\left(2\frac{1}{2}, -4\frac{1}{2}\right)\)B1✓ Can score by sub \(x = 2\frac{1}{2}\) into original but not by differentiation
[4]
(ii) \(2x^2 - 10x + 8 - kx = 0\)M1 Sets equation to 0 and uses discriminant correctly
Use of "\(b^2 - 4ac\)"M1
\((-10-k)^2 - 64 < 0\) or \(k^2 + 20k + 36 < 0\)A1 Realises discriminant \(< 0\). Allow \(\leq\) co Dep on 1st M1 only
\(\rightarrow k = -18\) or \(-2\)A1 co
\(-18 < k < -2\)A1
[4]
$2x^2 - 10x + 8 \rightarrow a(x+b)^2 + c$ | | |
(i) $a = 2, b = -\frac{1}{2}, c = -4\frac{1}{2}$ | 3 × B1 | Or $2\left[x - 2\frac{1}{2}\right]^2 - 4\frac{1}{2}$ |
$\rightarrow$ min value is $-4\frac{1}{2}$ Allow $\left(2\frac{1}{2}, -4\frac{1}{2}\right)$ | B1✓ | Can score by sub $x = 2\frac{1}{2}$ into original but not by differentiation |
| | [4] |
(ii) $2x^2 - 10x + 8 - kx = 0$ | M1 | Sets equation to 0 and uses discriminant correctly |
Use of "$b^2 - 4ac$" | M1 | |
$(-10-k)^2 - 64 < 0$ or $k^2 + 20k + 36 < 0$ | A1 | Realises discriminant $< 0$. Allow $\leq$ co Dep on 1st M1 only |
$\rightarrow k = -18$ or $-2$ | A1 | co |
$-18 < k < -2$ | A1 | |
| | [4] |
8 (i) Express $2 x ^ { 2 } - 10 x + 8$ in the form $a ( x + b ) ^ { 2 } + c$, where $a , b$ and $c$ are constants, and use your answer to state the minimum value of $2 x ^ { 2 } - 10 x + 8$.\\
(ii) Find the set of values of $k$ for which the equation $2 x ^ { 2 } - 10 x + 8 = k x$ has no real roots.

\hfill \mbox{\textit{CAIE P1 2014 Q8 [8]}}