Standard +0.3 This is a straightforward application of Hooke's law and Newton's second law. Students must find the extension (6 - 2.5 = 3.5 m), calculate the tension using T = (λx)/l, then apply F = ma with weight and tension. It's a standard single-step mechanics problem requiring only direct formula application, making it slightly easier than average.
1 One end of a light elastic rope of natural length 2.5 m and modulus of elasticity 80 N is attached to a fixed point \(A\). A stone \(S\) of mass 8 kg is attached to the other end of the rope. \(S\) is held at a point 6 m vertically below \(A\) and then released. Find the initial acceleration of \(S\).
1 One end of a light elastic rope of natural length 2.5 m and modulus of elasticity 80 N is attached to a fixed point $A$. A stone $S$ of mass 8 kg is attached to the other end of the rope. $S$ is held at a point 6 m vertically below $A$ and then released. Find the initial acceleration of $S$.
\hfill \mbox{\textit{CAIE M2 2008 Q1 [4]}}