CAIE M2 2013 June — Question 2 7 marks

Exam BoardCAIE
ModuleM2 (Mechanics 2)
Year2013
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVariable Force
TypeElastic string with variable force
DifficultyStandard +0.3 This is a straightforward elastic string problem requiring standard mechanics techniques: (i) uses F=ma with weight only (string slack), (ii) uses energy conservation with elastic PE. Both parts are direct applications of standard M2 formulas with clear setup and minimal problem-solving insight required.
Spec6.02h Elastic PE: 1/2 k x^26.02i Conservation of energy: mechanical energy principle6.02j Conservation with elastics: springs and strings

2 A particle \(P\) of mass 0.4 kg is attached to one end of a light elastic string of natural length 1.2 m and modulus of elasticity 19.2 N . The other end of the string is attached to a fixed point \(A\). The particle \(P\) is released from rest at the point 2.7 m vertically above \(A\). Calculate
  1. the initial acceleration of \(P\),
  2. the speed of \(P\) when it reaches \(A\).

Question 2:
Part (i)
AnswerMarks Guidance
AnswerMark Guidance
\(T = 19.2 \times (2.7 - 1.2)/1.2\)B1 \(T = 24\) N
\(0.4a = 0.4g + T\)M1 Newton's Second Law with 3 terms
\(a = 70 \text{ ms}^{-2}\)A1 [3]
Part (ii)
AnswerMarks Guidance
AnswerMark Guidance
\(19.2(2.7-1.2)^2/(2 \times 1.2)\)B1 Initial EE = 18
M1For a 3 term energy equation
\(0.4v^2/2 = 0.4g \times 2.7 + 19.2 \times (2.7-1.2)^2/(2 \times 1.2)\)A1
\(v = 12 \text{ ms}^{-1}\)A1 [4]
Total: [7]
## Question 2:

### Part (i)
| Answer | Mark | Guidance |
|--------|------|----------|
| $T = 19.2 \times (2.7 - 1.2)/1.2$ | B1 | $T = 24$ N |
| $0.4a = 0.4g + T$ | M1 | Newton's Second Law with 3 terms |
| $a = 70 \text{ ms}^{-2}$ | A1 [3] | |

### Part (ii)
| Answer | Mark | Guidance |
|--------|------|----------|
| $19.2(2.7-1.2)^2/(2 \times 1.2)$ | B1 | Initial EE = 18 |
| | M1 | For a 3 term energy equation |
| $0.4v^2/2 = 0.4g \times 2.7 + 19.2 \times (2.7-1.2)^2/(2 \times 1.2)$ | A1 | |
| $v = 12 \text{ ms}^{-1}$ | A1 [4] | |

**Total: [7]**

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2 A particle $P$ of mass 0.4 kg is attached to one end of a light elastic string of natural length 1.2 m and modulus of elasticity 19.2 N . The other end of the string is attached to a fixed point $A$. The particle $P$ is released from rest at the point 2.7 m vertically above $A$. Calculate\\
(i) the initial acceleration of $P$,\\
(ii) the speed of $P$ when it reaches $A$.

\hfill \mbox{\textit{CAIE M2 2013 Q2 [7]}}