CAIE M2 2007 June — Question 1 4 marks

Exam BoardCAIE
ModuleM2 (Mechanics 2)
Year2007
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCentre of Mass 2
TypeRotating lamina about fixed axis
DifficultyModerate -0.8 This is a straightforward two-part question requiring recall of a standard formula for the centre of mass of a semicircular lamina (4r/3π from the diameter) and basic circular motion (v = rω). Both parts are direct applications with no problem-solving or novel insight required, making it easier than average.
Spec6.04b Find centre of mass: using symmetry6.05a Angular velocity: definitions

1 \includegraphics[max width=\textwidth, alt={}, center]{57f7ca89-f028-447a-9ac9-55f931201e6b-2_467_645_274_749} A uniform semicircular lamina has radius 5 m . The lamina rotates in a horizontal plane about a vertical axis through \(O\), the mid-point of its diameter. The angular speed of the lamina is \(4 \mathrm { rad } \mathrm { s } ^ { - 1 }\) (see diagram). Find
  1. the distance of the centre of mass of the lamina from \(O\),
  2. the speed with which the centre of mass of the lamina is moving.

Question 1:
Part (i)
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\bar{r} = \frac{2 \times 5 \sin 90°}{3 \times \pi/2}\)M1 For using \(\bar{r} = \frac{2r\sin\alpha}{3\alpha}\)
Distance is 2.12 mA1 Accept \(20/3\pi\)
Part (ii)
AnswerMarks Guidance
Answer/WorkingMark Guidance
M1For using \(v = r\omega\)
Speed is \(8.49 \text{ ms}^{-1}\)A1ft 2
Total: 4 marks
## Question 1:

### Part (i)
| Answer/Working | Mark | Guidance |
|---|---|---|
| $\bar{r} = \frac{2 \times 5 \sin 90°}{3 \times \pi/2}$ | M1 | For using $\bar{r} = \frac{2r\sin\alpha}{3\alpha}$ |
| Distance is 2.12 m | A1 | Accept $20/3\pi$ |

### Part (ii)
| Answer/Working | Mark | Guidance |
|---|---|---|
| | M1 | For using $v = r\omega$ |
| Speed is $8.49 \text{ ms}^{-1}$ | A1ft | 2 | ft their answer to part (i) |

**Total: 4 marks**

---
1\\
\includegraphics[max width=\textwidth, alt={}, center]{57f7ca89-f028-447a-9ac9-55f931201e6b-2_467_645_274_749}

A uniform semicircular lamina has radius 5 m . The lamina rotates in a horizontal plane about a vertical axis through $O$, the mid-point of its diameter. The angular speed of the lamina is $4 \mathrm { rad } \mathrm { s } ^ { - 1 }$ (see diagram). Find\\
(i) the distance of the centre of mass of the lamina from $O$,\\
(ii) the speed with which the centre of mass of the lamina is moving.

\hfill \mbox{\textit{CAIE M2 2007 Q1 [4]}}