CAIE M1 2019 November — Question 5 8 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2019
SessionNovember
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPower and driving force
TypeCyclist or runner: find resistance or speed
DifficultyModerate -0.3 This is a straightforward multi-part mechanics question requiring standard application of P=Fv and F=ma with constant resistance. Part (i) uses Newton's second law with power equation, part (ii) finds steady speed (zero acceleration), and part (iii) adds an incline component. All steps are routine M1 techniques with no novel problem-solving required, making it slightly easier than average.
Spec3.02d Constant acceleration: SUVAT formulae6.02l Power and velocity: P = Fv

5 A cyclist is travelling along a straight horizontal road. The total mass of the cyclist and his bicycle is 80 kg . His power output is a constant 240 W . His acceleration when he is travelling at \(6 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) is \(0.3 \mathrm {~m} \mathrm {~s} ^ { - 2 }\).
  1. Show that the resistance to the cyclist's motion is 16 N .
  2. Find the steady speed that the cyclist can maintain if his power output and the resistance force are both unchanged.
  3. The cyclist later ascends a straight hill inclined at \(3 ^ { \circ }\) to the horizontal. His power output and the resistance force are still both unchanged. Find his acceleration when he is travelling at \(4 \mathrm {~ms} ^ { - 1 }\).

Question 5(i):
AnswerMarks Guidance
AnswerMarks Guidance
Driving force \(= \frac{240}{6}\) \((= 40\text{ N})\)B1 Use of power \(=\) force \(\times\) velocity
\([40 - R = 80\times0.3]\)M1 Use of Newton's Second Law (3 terms)
Resistance is \(16\) NA1 AG
Question 5(ii):
AnswerMarks Guidance
AnswerMarks Guidance
\(\left[\frac{240}{v} = 16\right]\)M1 Use of \(P=Fv\) with DF \(=\) resistance
Steady speed is \(15 \text{ ms}^{-1}\)A1
Question 5(iii):
AnswerMarks Guidance
AnswerMarks Guidance
Use of Newton's Second LawM1 (4 terms)
\(\frac{240}{4} - 16 - 80g\sin3 = 80a\)A1
Acceleration is \(0.0266 \text{ ms}^{-2}\)A1
## Question 5(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Driving force $= \frac{240}{6}$ $(= 40\text{ N})$ | B1 | Use of power $=$ force $\times$ velocity |
| $[40 - R = 80\times0.3]$ | M1 | Use of Newton's Second Law (3 terms) |
| Resistance is $16$ N | A1 | AG |

## Question 5(ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\left[\frac{240}{v} = 16\right]$ | M1 | Use of $P=Fv$ with DF $=$ resistance |
| Steady speed is $15 \text{ ms}^{-1}$ | A1 | |

## Question 5(iii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Use of Newton's Second Law | M1 | (4 terms) |
| $\frac{240}{4} - 16 - 80g\sin3 = 80a$ | A1 | |
| Acceleration is $0.0266 \text{ ms}^{-2}$ | A1 | |
5 A cyclist is travelling along a straight horizontal road. The total mass of the cyclist and his bicycle is 80 kg . His power output is a constant 240 W . His acceleration when he is travelling at $6 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ is $0.3 \mathrm {~m} \mathrm {~s} ^ { - 2 }$.\\
(i) Show that the resistance to the cyclist's motion is 16 N .\\

(ii) Find the steady speed that the cyclist can maintain if his power output and the resistance force are both unchanged.\\

(iii) The cyclist later ascends a straight hill inclined at $3 ^ { \circ }$ to the horizontal. His power output and the resistance force are still both unchanged. Find his acceleration when he is travelling at $4 \mathrm {~ms} ^ { - 1 }$.\\

\hfill \mbox{\textit{CAIE M1 2019 Q5 [8]}}