CAIE M1 2015 November — Question 5 8 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2015
SessionNovember
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNewton's laws and connected particles
TypeParticle on incline, hanging counterpart
DifficultyStandard +0.3 This is a standard connected particles problem requiring Newton's second law applied to both particles, solving simultaneous equations for tension and acceleration, then using kinematics after the string breaks. While multi-step, it follows a routine template for M1 connected particles questions with no novel insights required, making it slightly easier than average.
Spec3.02d Constant acceleration: SUVAT formulae3.03k Connected particles: pulleys and equilibrium3.03l Newton's third law: extend to situations requiring force resolution

5 \includegraphics[max width=\textwidth, alt={}, center]{48f66bd5-33c1-4ce9-85f9-69faf10e871c-3_259_828_1288_660} A smooth inclined plane of length 2.5 m is fixed with one end on the horizontal floor and the other end at a height of 0.7 m above the floor. Particles \(P\) and \(Q\), of masses 0.5 kg and 0.1 kg respectively, are attached to the ends of a light inextensible string which passes over a small smooth pulley fixed at the top of the plane. Particle \(Q\) is held at rest on the floor vertically below the pulley. The string is taut and \(P\) is at rest on the plane (see diagram). \(Q\) is released and starts to move vertically upwards towards the pulley and \(P\) moves down the plane.
  1. Find the tension in the string and the magnitude of the acceleration of the particles before \(Q\) reaches the pulley. At the instant just before \(Q\) reaches the pulley the string breaks; \(P\) continues to move down the plane and reaches the floor with a speed of \(2 \mathrm {~m} \mathrm {~s} ^ { - 1 }\).
  2. Find the length of the string.

Question 5:
Part (i)
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(0.5g \times \frac{7}{25} - T = 0.5a\) and \(T - 0.1g = 0.1a\)M1 For applying Newton's 2nd law to \(P\) or to \(Q\) or for applying N2 to the system; any two correct, allow \(\sin16.3\) for \(7/25\)
\(1.4 - 1 = 0.6a\)A1
\(a = \frac{2}{3}\text{ ms}^{-2}\)B1 For eliminating \(T\) and obtaining \(a\)
M1For substituting for \(a\) to find \(T\)
Tension is \(1.07\text{ N}\)A1 Allow \(T = 16/15\text{ N}\)
Total: 5
Part (ii)
AnswerMarks Guidance
Answer/WorkingMark Guidance
\([v^2 = 2 \times \left(\frac{2}{3}\right) \times 0.7]\)M1 For using \(v^2 = u^2 + 2as\) to find the speed of the particles immediately before the string breaks
\([2^2 = 2 \times \frac{2}{3} \times 0.7 + 2 \times 0.28g \times s]\)M1 For applying \(v^2 = u^2 + 2as\) for the motion of \(P\) when the string is slack and \(s\) is the distance travelled by \(P\) after the break until it reaches the floor
Length of string \(= 2.5 - s = 1.95\text{ m}\)A1 Allow length \(= 41/21\text{ m}\)
Total: 3
# Question 5:

## Part (i)
| Answer/Working | Mark | Guidance |
|---|---|---|
| $0.5g \times \frac{7}{25} - T = 0.5a$ and $T - 0.1g = 0.1a$ | M1 | For applying Newton's 2nd law to $P$ **or** to $Q$ **or** for applying N2 to the system; any two correct, allow $\sin16.3$ for $7/25$ |
| $1.4 - 1 = 0.6a$ | A1 | |
| $a = \frac{2}{3}\text{ ms}^{-2}$ | B1 | For eliminating $T$ and obtaining $a$ |
| | M1 | For substituting for $a$ to find $T$ |
| Tension is $1.07\text{ N}$ | A1 | Allow $T = 16/15\text{ N}$ |
| | **Total: 5** | |

## Part (ii)
| Answer/Working | Mark | Guidance |
|---|---|---|
| $[v^2 = 2 \times \left(\frac{2}{3}\right) \times 0.7]$ | M1 | For using $v^2 = u^2 + 2as$ to find the speed of the particles immediately before the string breaks |
| $[2^2 = 2 \times \frac{2}{3} \times 0.7 + 2 \times 0.28g \times s]$ | M1 | For applying $v^2 = u^2 + 2as$ for the motion of $P$ when the string is slack and $s$ is the distance travelled by $P$ after the break until it reaches the floor |
| Length of string $= 2.5 - s = 1.95\text{ m}$ | A1 | Allow length $= 41/21\text{ m}$ |
| | **Total: 3** | |

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\includegraphics[max width=\textwidth, alt={}, center]{48f66bd5-33c1-4ce9-85f9-69faf10e871c-3_259_828_1288_660}

A smooth inclined plane of length 2.5 m is fixed with one end on the horizontal floor and the other end at a height of 0.7 m above the floor. Particles $P$ and $Q$, of masses 0.5 kg and 0.1 kg respectively, are attached to the ends of a light inextensible string which passes over a small smooth pulley fixed at the top of the plane. Particle $Q$ is held at rest on the floor vertically below the pulley. The string is taut and $P$ is at rest on the plane (see diagram). $Q$ is released and starts to move vertically upwards towards the pulley and $P$ moves down the plane.\\
(i) Find the tension in the string and the magnitude of the acceleration of the particles before $Q$ reaches the pulley.

At the instant just before $Q$ reaches the pulley the string breaks; $P$ continues to move down the plane and reaches the floor with a speed of $2 \mathrm {~m} \mathrm {~s} ^ { - 1 }$.\\
(ii) Find the length of the string.

\hfill \mbox{\textit{CAIE M1 2015 Q5 [8]}}