CAIE M1 2015 November — Question 1 5 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2015
SessionNovember
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMoments
TypeCoplanar forces in equilibrium
DifficultyModerate -0.3 This is a standard coplanar forces equilibrium problem requiring resolution in two perpendicular directions. While it involves trigonometry and simultaneous equations, it's a routine textbook exercise with clear methodology (resolve horizontally and vertically, solve for unknowns). The 'show that' part guides students to one answer, making it slightly easier than average A-level mechanics questions.
Spec3.03e Resolve forces: two dimensions3.03m Equilibrium: sum of resolved forces = 0

1 \includegraphics[max width=\textwidth, alt={}, center]{48f66bd5-33c1-4ce9-85f9-69faf10e871c-2_558_529_258_808} Four horizontal forces act at a point \(O\) and are in equilibrium. The magnitudes of the forces are \(F \mathrm {~N}\), \(G \mathrm {~N} , 15 \mathrm {~N}\) and \(F \mathrm {~N}\), and the forces act in directions as shown in the diagram.
  1. Show that \(F = 41.0\), correct to 3 significant figures.
  2. Find the value of \(G\).

Question 1:
Part (i)
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(15 + F\cos60° = F\cos30°\)M1 For resolving forces in the \(x\) direction
\(F = 41.0\)A1 AG \(F = 15(1 + \sqrt{3})\)
Total: 3
Part (ii)
AnswerMarks Guidance
Answer/WorkingMark Guidance
\([G = F(\sin30° + \sin60°)]\)M1 For resolving forces in the \(y\) direction
\(G = 56.0\)A1 Allow \(15(2 + \sqrt{3})\)
Total: 2
# Question 1:

## Part (i)
| Answer/Working | Mark | Guidance |
|---|---|---|
| $15 + F\cos60° = F\cos30°$ | M1 | For resolving forces in the $x$ direction |
| $F = 41.0$ | A1 | AG $F = 15(1 + \sqrt{3})$ |
| | **Total: 3** | |

## Part (ii)
| Answer/Working | Mark | Guidance |
|---|---|---|
| $[G = F(\sin30° + \sin60°)]$ | M1 | For resolving forces in the $y$ direction |
| $G = 56.0$ | A1 | Allow $15(2 + \sqrt{3})$ |
| | **Total: 2** | |

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1\\
\includegraphics[max width=\textwidth, alt={}, center]{48f66bd5-33c1-4ce9-85f9-69faf10e871c-2_558_529_258_808}

Four horizontal forces act at a point $O$ and are in equilibrium. The magnitudes of the forces are $F \mathrm {~N}$, $G \mathrm {~N} , 15 \mathrm {~N}$ and $F \mathrm {~N}$, and the forces act in directions as shown in the diagram.\\
(i) Show that $F = 41.0$, correct to 3 significant figures.\\
(ii) Find the value of $G$.

\hfill \mbox{\textit{CAIE M1 2015 Q1 [5]}}