CAIE P1 2013 June — Question 8 8 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2013
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicChain Rule
TypeOptimization with constraint
DifficultyStandard +0.3 This is a standard optimization problem requiring expressing surface area in terms of one variable using a constraint, then differentiating and finding stationary points. The algebra is straightforward (substituting h=250/r² into S=2πr²+2πrh), differentiation is routine, and determining nature via second derivative is a textbook technique. Slightly above average difficulty due to multi-step nature but requires no novel insight.
Spec1.07n Stationary points: find maxima, minima using derivatives1.07o Increasing/decreasing: functions using sign of dy/dx

8 The volume of a solid circular cylinder of radius \(r \mathrm {~cm}\) is \(250 \pi \mathrm {~cm} ^ { 3 }\).
  1. Show that the total surface area, \(S \mathrm {~cm} ^ { 2 }\), of the cylinder is given by $$S = 2 \pi r ^ { 2 } + \frac { 500 \pi } { r }$$
  2. Given that \(r\) can vary, find the stationary value of \(S\).
  3. Determine the nature of this stationary value.

(i) \(\pi r^2 h = 250\pi \rightarrow h = \frac{250}{r^2}\)
\(\rightarrow S = 2\pi rh + 2\pi r^2\)
AnswerMarks Guidance
\(\rightarrow S = 2\pi r^2 + \frac{500\pi}{r}\)M1 M1 Makes \(h\) the subject. \(\pi r^2 h\) must be right. Ans given – check all formulae
[2]
(ii) \(\frac{dS}{dr} = 4\pi r - \frac{500\pi}{r^2}\)B1 B1 B1 for each term
\(0\) when \(r^3 = 125 \rightarrow r = 5\) → \(S = 150\pi\)M1 A1 Sets differential to 0 + attempt at soln
[4]
(iii) \(\frac{d^2S}{dr^2} = 4\pi + \frac{1000\pi}{r^3}\). This is positive → MinimumM1 A1 Any valid method. 2nd differential must be correct – no need for numerical answer or correct \(r\)
[2]
(i) $\pi r^2 h = 250\pi \rightarrow h = \frac{250}{r^2}$

$\rightarrow S = 2\pi rh + 2\pi r^2$

$\rightarrow S = 2\pi r^2 + \frac{500\pi}{r}$ | M1 M1 | Makes $h$ the subject. $\pi r^2 h$ must be right. Ans given – check all formulae

[2] |

(ii) $\frac{dS}{dr} = 4\pi r - \frac{500\pi}{r^2}$ | B1 B1 | B1 for each term

$0$ when $r^3 = 125 \rightarrow r = 5$ → $S = 150\pi$ | M1 A1 | Sets differential to 0 + attempt at soln

[4] |

(iii) $\frac{d^2S}{dr^2} = 4\pi + \frac{1000\pi}{r^3}$. This is positive → Minimum | M1 A1 | Any valid method. 2nd differential must be correct – no need for numerical answer or correct $r$

[2] |

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8 The volume of a solid circular cylinder of radius $r \mathrm {~cm}$ is $250 \pi \mathrm {~cm} ^ { 3 }$.\\
(i) Show that the total surface area, $S \mathrm {~cm} ^ { 2 }$, of the cylinder is given by

$$S = 2 \pi r ^ { 2 } + \frac { 500 \pi } { r }$$

(ii) Given that $r$ can vary, find the stationary value of $S$.\\
(iii) Determine the nature of this stationary value.

\hfill \mbox{\textit{CAIE P1 2013 Q8 [8]}}