CAIE P1 2013 June — Question 2 5 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2013
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Theorem (positive integer n)
TypeProduct with reciprocal term binomial
DifficultyModerate -0.3 This is a straightforward binomial expansion question requiring identification of the correct term in part (i) using the binomial theorem formula, then a simple multiplication in part (ii). While it involves negative powers and careful algebraic manipulation, it's a standard textbook exercise with no novel problem-solving required, making it slightly easier than average.
Spec1.04a Binomial expansion: (a+b)^n for positive integer n

2 Find the coefficient of \(x ^ { 2 }\) in the expansion of
  1. \(\left( 2 x - \frac { 1 } { 2 x } \right) ^ { 6 }\),
  2. \(\left( 1 + x ^ { 2 } \right) \left( 2 x - \frac { 1 } { 2 x } \right) ^ { 6 }\).

\(\left(2x - \frac{1}{2x}\right)^6\)
AnswerMarks Guidance
(i) Coeff of \(x^2\) is \(15 \times 16 \times (-\frac{1}{2})^2 = 60\)B1 B1 M1 A1 B1 for 2/3 parts. B1 unsimplified. Needs to consider the constant term
(ii) Constant term is \(20 \times 8x^3 \times (-1 + 8x^3) \times (1 + x^2)\) needs to consider 2 terms → \(60 - 20 = 40\)[3]
$\left(2x - \frac{1}{2x}\right)^6$

(i) Coeff of $x^2$ is $15 \times 16 \times (-\frac{1}{2})^2 = 60$ | B1 B1 M1 A1 | B1 for 2/3 parts. B1 unsimplified. Needs to consider the constant term

(ii) Constant term is $20 \times 8x^3 \times (-1 + 8x^3) \times (1 + x^2)$ needs to consider 2 terms → $60 - 20 = 40$ | [3] |

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2 Find the coefficient of $x ^ { 2 }$ in the expansion of\\
(i) $\left( 2 x - \frac { 1 } { 2 x } \right) ^ { 6 }$,\\
(ii) $\left( 1 + x ^ { 2 } \right) \left( 2 x - \frac { 1 } { 2 x } \right) ^ { 6 }$.

\hfill \mbox{\textit{CAIE P1 2013 Q2 [5]}}