CAIE M1 2011 November — Question 1 3 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2011
SessionNovember
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicWork done and energy
TypeWork done by constant force - find work done
DifficultyModerate -0.8 This is a straightforward application of the work formula W = Fs cos θ, requiring only the identification that distance = speed × time (16m), then calculating 25 × 16 × cos(20°). It involves basic recall and one simple multi-step calculation with no problem-solving insight needed, making it easier than average.
Spec6.02b Calculate work: constant force, resolved component

1 One end of a light inextensible string is attached to a block. The string is used to pull the block along a horizontal surface with a speed of \(2 \mathrm {~m} \mathrm {~s} ^ { - 1 }\). The string makes an angle of \(20 ^ { \circ }\) with the horizontal and the tension in the string is 25 N . Find the work done by the tension in a period of 8 seconds.

AnswerMarks Guidance
\(d = 2 \times 8\)B1
\([25 \times 16\cos 20°]\)M1 For using \(WD = Fd\cos\alpha\)
Work done is 376 JA1 3
| $d = 2 \times 8$ | B1 | |
| $[25 \times 16\cos 20°]$ | M1 | For using $WD = Fd\cos\alpha$ |
| Work done is 376 J | A1 | 3 |

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1 One end of a light inextensible string is attached to a block. The string is used to pull the block along a horizontal surface with a speed of $2 \mathrm {~m} \mathrm {~s} ^ { - 1 }$. The string makes an angle of $20 ^ { \circ }$ with the horizontal and the tension in the string is 25 N . Find the work done by the tension in a period of 8 seconds.

\hfill \mbox{\textit{CAIE M1 2011 Q1 [3]}}