Standard +0.3 This is a straightforward application of the power-force-velocity relationship (P=Fv) combined with Newton's second law on an incline. Students must resolve forces parallel to the slope, apply F=ma to find the driving force, then use P=Fv to find velocity. It requires multiple standard techniques but follows a predictable structure with no conceptual surprises, making it slightly easier than average.
3 A car of mass 1250 kg travels down a straight hill with the engine working at a power of 22 kW . The hill is inclined at \(3 ^ { \circ }\) to the horizontal and the resistance to motion of the car is 1130 N . Find the speed of the car at an instant when its acceleration is \(0.2 \mathrm {~m} \mathrm {~s} ^ { - 2 }\).
3 A car of mass 1250 kg travels down a straight hill with the engine working at a power of 22 kW . The hill is inclined at $3 ^ { \circ }$ to the horizontal and the resistance to motion of the car is 1130 N . Find the speed of the car at an instant when its acceleration is $0.2 \mathrm {~m} \mathrm {~s} ^ { - 2 }$.
\hfill \mbox{\textit{CAIE M1 2004 Q3 [5]}}