Moderate -0.8 This is a standard two-particle pulley system with straightforward application of Newton's second law to both particles. The setup is simple (one particle on smooth horizontal table, one hanging), requiring only F=ma for each particle and solving two simultaneous equations. It's easier than average because there are no complications like friction, inclined planes, or additional forces, and the method is routine for M1 students.
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\includegraphics[max width=\textwidth, alt={}, center]{38ece0f6-1c29-4e7a-9d66-16c3e2b695f9-2_200_529_269_808}
Two particles \(P\) and \(Q\), of masses 1.7 kg and 0.3 kg respectively, are connected by a light inextensible string. \(P\) is held on a smooth horizontal table with the string taut and passing over a small smooth pulley fixed at the edge of the table. \(Q\) is at rest vertically below the pulley. \(P\) is released. Find the acceleration of the particles and the tension in the string.
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\includegraphics[max width=\textwidth, alt={}, center]{38ece0f6-1c29-4e7a-9d66-16c3e2b695f9-2_200_529_269_808}
Two particles $P$ and $Q$, of masses 1.7 kg and 0.3 kg respectively, are connected by a light inextensible string. $P$ is held on a smooth horizontal table with the string taut and passing over a small smooth pulley fixed at the edge of the table. $Q$ is at rest vertically below the pulley. $P$ is released. Find the acceleration of the particles and the tension in the string.
\hfill \mbox{\textit{CAIE M1 2004 Q1 [5]}}