CAIE P1 2013 June — Question 2 5 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2013
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Theorem (positive integer n)
TypeCoefficient zero after multiplying binomial
DifficultyModerate -0.3 Part (i) is straightforward binomial expansion requiring direct application of the formula for three terms. Part (ii) requires multiplying the expansion by (1-x) and setting the x² coefficient to zero, which involves collecting like terms and solving a simple equation. This is a standard textbook exercise with minimal problem-solving demand, making it slightly easier than average.
Spec1.04a Binomial expansion: (a+b)^n for positive integer n

2
  1. In the expression \(( 1 - p x ) ^ { 6 } , p\) is a non-zero constant. Find the first three terms when \(( 1 - p x ) ^ { 6 }\) is expanded in ascending powers of \(x\).
  2. It is given that the coefficient of \(x ^ { 2 }\) in the expansion of \(( 1 - x ) ( 1 - p x ) ^ { 6 }\) is zero. Find the value of \(p\).

AnswerMarks Guidance
(i) \(1 - 6pyx + 15p^2x^2\)B1B1 Simplification of \(nCr\) can be scored in (ii)
[2]
AnswerMarks Guidance
(ii) \(15p^2 \times 1 - 6p \times -1\) or \(3p(5p + 2) = 0\)M1 DM1 Obtain & attempt to solve quadratic
\(p = -\frac{2}{5}\) oeA1 Allow \(p = 0\) in addition
[3]
(i) $1 - 6pyx + 15p^2x^2$ | B1B1 | Simplification of $nCr$ can be scored in (ii)
[2]

(ii) $15p^2 \times 1 - 6p \times -1$ or $3p(5p + 2) = 0$ | M1 DM1 | Obtain & attempt to solve quadratic
$p = -\frac{2}{5}$ oe | A1 | Allow $p = 0$ in addition
[3]
2 (i) In the expression $( 1 - p x ) ^ { 6 } , p$ is a non-zero constant. Find the first three terms when $( 1 - p x ) ^ { 6 }$ is expanded in ascending powers of $x$.\\
(ii) It is given that the coefficient of $x ^ { 2 }$ in the expansion of $( 1 - x ) ( 1 - p x ) ^ { 6 }$ is zero. Find the value of $p$.

\hfill \mbox{\textit{CAIE P1 2013 Q2 [5]}}