OCR Further Pure Core 1 2021 June — Question 1 9 marks

Exam BoardOCR
ModuleFurther Pure Core 1 (Further Pure Core 1)
Year2021
SessionJune
Marks9
TopicPolar coordinates
TypeArea enclosed by polar curve
DifficultyStandard +0.3 This is a straightforward Further Maths polar coordinates question requiring standard techniques: finding maximum by differentiation (or recognizing sin 2θ maximizes at π/4), evaluating r, and applying the polar area formula ½∫r²dθ. While polar coordinates is a Further Maths topic, the execution involves routine calculus with no novel problem-solving, making it slightly easier than average overall.
Spec1.07n Stationary points: find maxima, minima using derivatives4.09b Sketch polar curves: r = f(theta)4.09c Area enclosed: by polar curve

The equation of the curve shown on the graph is, in polar coordinates, \(r = 3\sin 2\theta\) for \(0 \leqslant \theta \leqslant \frac{1}{2}\pi\). \includegraphics{figure_1}
  1. The greatest value of \(r\) on the curve occurs at the point \(P\).
    1. Show that \(\theta = \frac{1}{4}\pi\) at the point \(P\). [2]
    2. Find the value of \(r\) at the point \(P\). [1]
    3. Mark the point \(P\) on a copy of the graph. [1]
  2. In this question you must show detailed reasoning. Find the exact area of the region enclosed by the curve. [5]

The equation of the curve shown on the graph is, in polar coordinates, $r = 3\sin 2\theta$ for $0 \leqslant \theta \leqslant \frac{1}{2}\pi$.

\includegraphics{figure_1}

\begin{enumerate}[label=(\alph*)]
\item The greatest value of $r$ on the curve occurs at the point $P$.
\begin{enumerate}[label=(\roman*)]
\item Show that $\theta = \frac{1}{4}\pi$ at the point $P$. [2]
\item Find the value of $r$ at the point $P$. [1]
\item Mark the point $P$ on a copy of the graph. [1]
\end{enumerate}

\item In this question you must show detailed reasoning.

Find the exact area of the region enclosed by the curve. [5]
\end{enumerate}

\hfill \mbox{\textit{OCR Further Pure Core 1 2021 Q1 [9]}}