The equation of the curve shown on the graph is, in polar coordinates, \(r = 3\sin 2\theta\) for \(0 \leqslant \theta \leqslant \frac{1}{2}\pi\).
\includegraphics{figure_1}
- The greatest value of \(r\) on the curve occurs at the point \(P\).
- Show that \(\theta = \frac{1}{4}\pi\) at the point \(P\). [2]
- Find the value of \(r\) at the point \(P\). [1]
- Mark the point \(P\) on a copy of the graph. [1]
- In this question you must show detailed reasoning.
Find the exact area of the region enclosed by the curve. [5]