SPS SPS FM Pure 2026 November — Question 1 4 marks

Exam BoardSPS
ModuleSPS FM Pure (SPS FM Pure)
Year2026
SessionNovember
Marks4
TopicComplex Numbers Arithmetic
TypeLinear equations in z and z*
DifficultyModerate -0.3 This is a straightforward complex number equation requiring substitution of z = x + iy and its conjugate, then equating real and imaginary parts to solve a simple 2×2 system. It's slightly easier than average as it's purely procedural with no conceptual challenges, though the presence of the conjugate adds minor complexity beyond basic complex arithmetic.
Spec4.02a Complex numbers: real/imaginary parts, modulus, argument4.02e Arithmetic of complex numbers: add, subtract, multiply, divide

The complex number \(z\) satisfies the equation \(z + 2iz^* + 1 - 4i = 0\). You are given that \(z = x + iy\), where \(x\) and \(y\) are real numbers. Determine the values of \(x\) and \(y\). [4]

The complex number $z$ satisfies the equation $z + 2iz^* + 1 - 4i = 0$.

You are given that $z = x + iy$, where $x$ and $y$ are real numbers.

Determine the values of $x$ and $y$. [4]

\hfill \mbox{\textit{SPS SPS FM Pure 2026 Q1 [4]}}