SPS SPS FM Pure 2025 June — Question 14 5 marks

Exam BoardSPS
ModuleSPS FM Pure (SPS FM Pure)
Year2025
SessionJune
Marks5
TopicVectors 3D & Lines
TypeAngle with unknown parameter
DifficultyChallenging +1.8 This is a Further Maths vector problem requiring students to set up and solve a system using dot product formulas with the double angle constraint. It demands careful algebraic manipulation of cos(2θ) = 2cos²(θ) - 1 combined with perpendicularity conditions, going beyond routine dot product exercises but following a clear logical path once the setup is recognized.
Spec4.04c Scalar product: calculate and use for angles

The three dimensional non-zero vector \(\mathbf{u}\) has the following properties:
  • The angle \(\theta\) between \(\mathbf{u}\) and the vector \(\begin{pmatrix} 1 \\ 5 \\ 9 \end{pmatrix}\) is acute.
  • The (non-reflex) angle between \(\mathbf{u}\) and the vector \(\begin{pmatrix} 9 \\ 5 \\ 1 \end{pmatrix}\) is \(2\theta\).
  • \(\mathbf{u}\) is perpendicular to the vector \(\begin{pmatrix} 1 \\ 1 \\ 1 \end{pmatrix}\).
Find the angle \(\theta\). [5]

The three dimensional non-zero vector $\mathbf{u}$ has the following properties:
\begin{itemize}
\item The angle $\theta$ between $\mathbf{u}$ and the vector $\begin{pmatrix} 1 \\ 5 \\ 9 \end{pmatrix}$ is acute.

\item The (non-reflex) angle between $\mathbf{u}$ and the vector $\begin{pmatrix} 9 \\ 5 \\ 1 \end{pmatrix}$ is $2\theta$.

\item $\mathbf{u}$ is perpendicular to the vector $\begin{pmatrix} 1 \\ 1 \\ 1 \end{pmatrix}$.
\end{itemize}

Find the angle $\theta$.
[5]

\hfill \mbox{\textit{SPS SPS FM Pure 2025 Q14 [5]}}