SPS SPS FM Statistics 2025 April — Question 2 13 marks

Exam BoardSPS
ModuleSPS FM Statistics (SPS FM Statistics)
Year2025
SessionApril
Marks13
TopicMeasures of Location and Spread
TypeFind median and quartiles from stem-and-leaf diagram
DifficultyModerate -0.8 This is a straightforward descriptive statistics question requiring routine calculations from a stem-and-leaf diagram. All parts involve standard procedures (finding median, IQR, mean, standard deviation) with no problem-solving or novel insight required. The data is already organized, making calculations mechanical. This is easier than average A-level content, though the multi-part nature and calculator work prevent it from being trivial.
Spec2.02a Interpret single variable data: tables and diagrams2.02f Measures of average and spread2.02g Calculate mean and standard deviation

In a study of reaction times, 25 participants completed a test where their reaction times (in milliseconds) were recorded. The results are shown in the stem-and-leaf diagram below: 20 | 3 5 7 9 21 | 0 2 5 6 8 22 | 1 3 4 5 7 9 23 | 0 2 5 8 24 | 1 4 6 7 25 | 2 5 Key: 21 | 0 represents a reaction time of 210 milliseconds
  1. State the median reaction time. [1]
  2. Calculate the interquartile range of these reaction times. [2]
  3. Find the mean and standard deviation of these reaction times. [3]
  4. State one advantage of using a stem-and-leaf diagram to display this data rather than a frequency table. [1]
  5. One participant completed the test again and recorded a reaction time of 195 milliseconds. Add this result to the stem-and-leaf diagram and state the effect this would have on:
    1. the median
    2. the mean
    3. the standard deviation
    [4]
  6. Explain why the interquartile range might be preferred to the standard deviation as a measure of spread in this context [2]

In a study of reaction times, 25 participants completed a test where their reaction times (in milliseconds) were recorded. The results are shown in the stem-and-leaf diagram below:

20 | 3 5 7 9
21 | 0 2 5 6 8
22 | 1 3 4 5 7 9
23 | 0 2 5 8
24 | 1 4 6 7
25 | 2 5

Key: 21 | 0 represents a reaction time of 210 milliseconds

\begin{enumerate}[label=(\alph*)]
\item State the median reaction time. [1]

\item Calculate the interquartile range of these reaction times. [2]

\item Find the mean and standard deviation of these reaction times. [3]

\item State one advantage of using a stem-and-leaf diagram to display this data rather than a frequency table. [1]

\item One participant completed the test again and recorded a reaction time of 195 milliseconds. Add this result to the stem-and-leaf diagram and state the effect this would have on:
\begin{enumerate}[label=(\roman*)]
\item the median
\item the mean
\item the standard deviation
\end{enumerate}
[4]

\item Explain why the interquartile range might be preferred to the standard deviation as a measure of spread in this context [2]
\end{enumerate}

\hfill \mbox{\textit{SPS SPS FM Statistics 2025 Q2 [13]}}