SPS SPS FM 2025 February — Question 8 4 marks

Exam BoardSPS
ModuleSPS FM (SPS FM)
Year2025
SessionFebruary
Marks4
TopicComplex Numbers Argand & Loci
TypePerpendicular bisector locus
DifficultyModerate -0.3 This is a straightforward loci question requiring students to recognize that |z + i| = |z - 2i| represents the perpendicular bisector of two points, then find its equation. The inequality determines which half-plane to shade. While it involves complex numbers (a Further Maths topic), the geometric interpretation and algebraic manipulation are routine, making it slightly easier than an average A-level question.
Spec4.02k Argand diagrams: geometric interpretation4.02o Loci in Argand diagram: circles, half-lines

A locus \(C_1\) is defined by \(C_1 = \{z : |z + i| \leq |z - 2i|\}\).
  1. Indicate by shading on the Argand diagram below the region representing \(C_1\). [2] \includegraphics{figure_8}
  2. Find the cartesian equation of the boundary line of the region representing \(C_1\), giving your answer in the form \(ax + by + c = 0\). [2]

A locus $C_1$ is defined by $C_1 = \{z : |z + i| \leq |z - 2i|\}$.

\begin{enumerate}[label=(\roman*)]
\item Indicate by shading on the Argand diagram below the region representing $C_1$.
[2]

\includegraphics{figure_8}

\item Find the cartesian equation of the boundary line of the region representing $C_1$, giving your answer in the form $ax + by + c = 0$.
[2]
\end{enumerate}

\hfill \mbox{\textit{SPS SPS FM 2025 Q8 [4]}}