SPS SPS FM Pure 2023 June — Question 4 7 marks

Exam BoardSPS
ModuleSPS FM Pure (SPS FM Pure)
Year2023
SessionJune
Marks7
TopicLinear transformations
TypeExtract enlargement and rotation parameters
DifficultyStandard +0.3 This is a straightforward Further Maths matrix question testing standard techniques: computing a determinant (routine), using |det M| for area scaling (direct application), and decomposing a transformation matrix into enlargement and rotation (standard FM topic with clear method). All parts are bookwork-style with no novel problem-solving required, making it slightly easier than average even for FM.
Spec4.03d Linear transformations 2D: reflection, rotation, enlargement, shear4.03h Determinant 2x2: calculation4.03i Determinant: area scale factor and orientation

You are given that \(M = \begin{pmatrix} \frac{1}{\sqrt{3}} & -\sqrt{3} \\ \frac{1}{\sqrt{3}} & 1 \end{pmatrix}\).
  1. Show that \(M\) is non-singular. [2]
The hexagon \(R\) is transformed to the hexagon \(S\) by the transformation represented by the matrix \(M\). Given that the area of hexagon \(R\) is 5 square units,
  1. find the area of hexagon \(S\). [1]
The matrix \(M\) represents an enlargement, with centre \((0,0)\) and scale factor \(k\), where \(k > 0\), followed by a rotation anti-clockwise through an angle \(\theta\) about \((0,0)\).
  1. Find the value of \(k\). [2]
  2. Find the value of \(\theta\). [2]

You are given that $M = \begin{pmatrix} \frac{1}{\sqrt{3}} & -\sqrt{3} \\ \frac{1}{\sqrt{3}} & 1 \end{pmatrix}$.

\begin{enumerate}[label=(\roman*)]
\item Show that $M$ is non-singular. [2]
\end{enumerate}

The hexagon $R$ is transformed to the hexagon $S$ by the transformation represented by the matrix $M$.

Given that the area of hexagon $R$ is 5 square units,

\begin{enumerate}[label=(\roman*)]
\setcounter{enumi}{1}
\item find the area of hexagon $S$. [1]
\end{enumerate}

The matrix $M$ represents an enlargement, with centre $(0,0)$ and scale factor $k$, where $k > 0$, followed by a rotation anti-clockwise through an angle $\theta$ about $(0,0)$.

\begin{enumerate}[label=(\roman*)]
\setcounter{enumi}{2}
\item Find the value of $k$. [2]
\item Find the value of $\theta$. [2]
\end{enumerate}

\hfill \mbox{\textit{SPS SPS FM Pure 2023 Q4 [7]}}