SPS SPS FM Pure 2023 June — Question 3 6 marks

Exam BoardSPS
ModuleSPS FM Pure (SPS FM Pure)
Year2023
SessionJune
Marks6
TopicNewton-Raphson method
TypeNewton-Raphson with derivative given or simple
DifficultyStandard +0.3 This is a straightforward Further Maths question testing standard techniques: sign change for root existence, one iteration of Newton-Raphson with values provided, and proving uniqueness via monotonicity. All parts are routine applications of A-level methods with no novel problem-solving required, making it slightly easier than average.
Spec1.09a Sign change methods: locate roots1.09d Newton-Raphson method

You are given that \(f(x) = \ln(2x - 5) + 2x^2 - 30\), for \(x > 2.5\).
  1. Show that \(f(x) = 0\) has a root \(\alpha\) in the interval \([3.5, 4]\). [2]
A student takes 4 as the first approximation to \(\alpha\). Given \(f(4) = 3.099\) and \(f'(4) = 16.67\) to 4 significant figures,
  1. apply the Newton-Raphson procedure once to obtain a second approximation for \(\alpha\), giving your answer to 3 significant figures. [2]
  2. Show that \(\alpha\) is the only root of \(f(x) = 0\). [2]

You are given that $f(x) = \ln(2x - 5) + 2x^2 - 30$, for $x > 2.5$.

\begin{enumerate}[label=(\roman*)]
\item Show that $f(x) = 0$ has a root $\alpha$ in the interval $[3.5, 4]$. [2]
\end{enumerate}

A student takes 4 as the first approximation to $\alpha$.

Given $f(4) = 3.099$ and $f'(4) = 16.67$ to 4 significant figures,

\begin{enumerate}[label=(\roman*)]
\setcounter{enumi}{1}
\item apply the Newton-Raphson procedure once to obtain a second approximation for $\alpha$, giving your answer to 3 significant figures. [2]
\item Show that $\alpha$ is the only root of $f(x) = 0$. [2]
\end{enumerate}

\hfill \mbox{\textit{SPS SPS FM Pure 2023 Q3 [6]}}