SPS SPS SM 2022 October — Question 4 6 marks

Exam BoardSPS
ModuleSPS SM (SPS SM)
Year2022
SessionOctober
Marks6
TopicDiscriminant and conditions for roots
TypeShow discriminant inequality, then solve
DifficultyModerate -0.3 This is a standard discriminant problem requiring students to rearrange to standard form, apply b²-4ac > 0 for two distinct real roots, and solve a quadratic inequality. While it involves multiple steps (rearranging, discriminant condition, factorising/solving inequality), these are routine A-level techniques with no novel insight required. Slightly easier than average due to the straightforward application of well-practiced methods.
Spec1.02d Quadratic functions: graphs and discriminant conditions1.02g Inequalities: linear and quadratic in single variable1.02h Express solutions: using 'and', 'or', set and interval notation

The equation $$(k + 3)x^2 + 6x + k = 5$$, where \(k\) is a constant, has two distinct real solutions for \(x\).
  1. Show that \(k\) satisfies $$k^2 - 2k - 24 < 0$$ [4]
  2. Hence find the set of possible values of \(k\). [2]

The equation
$$(k + 3)x^2 + 6x + k = 5$$, where $k$ is a constant,

has two distinct real solutions for $x$.

\begin{enumerate}[label=(\alph*)]
\item Show that $k$ satisfies
$$k^2 - 2k - 24 < 0$$ [4]

\item Hence find the set of possible values of $k$. [2]
\end{enumerate}

\hfill \mbox{\textit{SPS SPS SM 2022 Q4 [6]}}