SPS SPS SM 2021 November — Question 6 7 marks

Exam BoardSPS
ModuleSPS SM (SPS SM)
Year2021
SessionNovember
Marks7
TopicTrig Proofs
TypeProve trigonometric identity
DifficultyChallenging +1.2 Part (a) requires proving a non-standard identity involving double angle formulas and reciprocal functions, demanding algebraic manipulation beyond routine exercises. Part (b) involves solving a trigonometric equation with compound angles requiring the application of addition formulas and careful algebraic work. Both parts require multi-step reasoning and are more challenging than typical A-level questions, but don't reach the level of requiring novel geometric insight or extended proof techniques.
Spec1.05o Trigonometric equations: solve in given intervals1.05p Proof involving trig: functions and identities

  1. Prove the following trigonometric identities. You must show all of your algebraic steps clearly. $$(\cos x + \sin x)(\cos x - \sec x) \equiv 2 \cot 2x$$ [3]
  2. Solve the following equation for \(x\) in the interval \(0 \leq x \leq \pi\). Giving your answers in terms of \(\pi\). $$\sin\left(2x + \frac{\pi}{6}\right) = \frac{1}{2}\sin\left(2x - \frac{\pi}{6}\right)$$ [4]

\begin{enumerate}[label=(\alph*)]
\item Prove the following trigonometric identities. You must show all of your algebraic steps clearly.
$$(\cos x + \sin x)(\cos x - \sec x) \equiv 2 \cot 2x$$ [3]

\item Solve the following equation for $x$ in the interval $0 \leq x \leq \pi$.
Giving your answers in terms of $\pi$.
$$\sin\left(2x + \frac{\pi}{6}\right) = \frac{1}{2}\sin\left(2x - \frac{\pi}{6}\right)$$ [4]
\end{enumerate}

\hfill \mbox{\textit{SPS SPS SM 2021 Q6 [7]}}