Express \(\frac{5x+7}{(x+3)(x+1)^2}\) in partial fractions.
In this question you must show all of your algebraic steps clearly. [3]
The function \(f(x) = \frac{2-6x+5x^2}{x^2(1-2x)}\) can be written in the form;
$$f(x) = \frac{-2}{x} + \frac{2}{x^2} + \frac{1}{1-2x}$$
Hence find the exact value of \(\int_2^3 \frac{2-6x+5x^2}{x^2(1-2x)} dx\) [3]
In this question you must show detailed algebraic reasoning.
Find the coordinates of any stationary points on the curve below.
$$y = (1 - 3x)(3 - x)^3$$
[5]
Find the equation of the normal to the curve \(y = 4 \ln(2x - 3)\) at the point where the curve crosses the \(x\) axis. Give your answer in the form \(ax + by + k = 0\) where \(a > 0\).
[5]
Write \(\log_{16} y - \log_{16} x\) as a single logarithm. [1]
Solve the simultaneous equations, giving your answers in an exact form.
$$\log_3 y = \log_3(9 - 6x) + 1$$
$$\log_{16} y - \log_{16} x = \frac{1}{4}$$
[3]
Prove the following trigonometric identities. You must show all of your algebraic steps clearly.
$$(\cos x + \sin x)(\cos x - \sec x) \equiv 2 \cot 2x$$ [3]
Solve the following equation for \(x\) in the interval \(0 \leq x \leq \pi\).
Giving your answers in terms of \(\pi\).
$$\sin\left(2x + \frac{\pi}{6}\right) = \frac{1}{2}\sin\left(2x - \frac{\pi}{6}\right)$$ [4]
The parametric equations of a curve are \(x = \theta \cos \theta\) and \(y = \sin \theta\)
Find the gradient of the curve at the point for which \(\theta = \pi\) [3]
A curve is defined parametrically by the equations;
$$x = \cos \theta \qquad y = \left(\frac{\sin \theta}{2}\right)\left(\sin \frac{\theta}{2}\right)$$
Show that the cartesian equation of the curve can be written as \(y^2 = \frac{1}{8}(1-x)^2(1+x)\) [4]