SPS SPS FM 2021 November — Question 5 4 marks

Exam BoardSPS
ModuleSPS FM (SPS FM)
Year2021
SessionNovember
Marks4
TopicIntegration using inverse trig and hyperbolic functions
TypeTrigonometric substitution to simplify integral
DifficultyStandard +0.8 This is a standard Further Maths integration technique requiring the substitution x = 4sin(θ), followed by using a trigonometric identity to simplify (16-x²)^(3/2) = 64cos³(θ), then integrating sec²(θ). While mechanical, it requires careful handling of limits and multiple steps, placing it moderately above average difficulty but still within the standard FM integration repertoire.
Spec4.08h Integration: inverse trig/hyperbolic substitutions

Use a trigonometrical substitution to show that $$\int_0^2 \frac{1}{(16 - x^2)^{\frac{3}{2}}} dx = \frac{1}{16\sqrt{3}}$$ [4 marks]

Use a trigonometrical substitution to show that
$$\int_0^2 \frac{1}{(16 - x^2)^{\frac{3}{2}}} dx = \frac{1}{16\sqrt{3}}$$
[4 marks]

\hfill \mbox{\textit{SPS SPS FM 2021 Q5 [4]}}