CAIE P1 2011 June — Question 6

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2011
SessionJune
TopicChain Rule

6 The variables \(x , y\) and \(z\) can take only positive values and are such that $$z = 3 x + 2 y \quad \text { and } \quad x y = 600 .$$
  1. Show that \(z = 3 x + \frac { 1200 } { x }\).
  2. Find the stationary value of \(z\) and determine its nature.