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LFM Pure
Chain Rule
Q6
CAIE P1 2011 June — Question 6
Exam Board
CAIE
Module
P1 (Pure Mathematics 1)
Year
2011
Session
June
Topic
Chain Rule
6 The variables \(x , y\) and \(z\) can take only positive values and are such that $$z = 3 x + 2 y \quad \text { and } \quad x y = 600 .$$
Show that \(z = 3 x + \frac { 1200 } { x }\).
Find the stationary value of \(z\) and determine its nature.
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