| Exam Board | SPS |
|---|---|
| Module | SPS SM Pure (SPS SM Pure) |
| Year | 2020 |
| Session | October |
| Marks | 5 |
| Topic | Product & Quotient Rules |
| Type | Find equation of tangent |
| Difficulty | Standard +0.3 This is a straightforward differentiation question requiring the product rule and chain rule to find dy/dx, then substituting x = -1 to find the gradient, and finally using y - y₁ = m(x - x₁). While it involves multiple techniques, it's a standard textbook exercise with no problem-solving insight required, making it slightly easier than average. |
| Spec | 1.07m Tangents and normals: gradient and equations1.07q Product and quotient rules: differentiation |
Find the equation of the tangent to the curve
$$y = 3x^2(x + 2)^6$$
at the point $(-1, 3)$, giving your answer in the form $y = mx + c$.
[5]
\hfill \mbox{\textit{SPS SPS SM Pure 2020 Q5 [5]}}