SPS SPS ASFM Mechanics 2021 May — Question 1 7 marks

Exam BoardSPS
ModuleSPS ASFM Mechanics (SPS ASFM Mechanics)
Year2021
SessionMay
Marks7
TopicRoots of polynomials
TypeFinding polynomial from root properties
DifficultyChallenging +1.3 This is a standard A-level Further Maths question on roots of polynomials requiring systematic application of Vieta's formulas and given identities. Part (i) is straightforward substitution once you identify the coefficients, while part (ii) requires forming a new cubic from symmetric functions of the cubed roots—a technique covered in FM syllabi but requiring careful algebraic manipulation across multiple steps.
Spec4.05a Roots and coefficients: symmetric functions

In this question you must show detailed reasoning. The equation \(x^3 + 3x^2 - 2x + 4 = 0\) has roots \(\alpha\), \(\beta\) and \(\gamma\).
  1. Using the identity \(\alpha^3 + \beta^3 + \gamma^3 = (\alpha + \beta + \gamma)^3 - 3(\alpha\beta + \beta\gamma + \gamma\alpha)(\alpha + \beta + \gamma) + 3\alpha\beta\gamma\) find the value of \(\alpha^3 + \beta^3 + \gamma^3\). [3]
  2. Given that \(\alpha^3\beta^3 + \beta^3\gamma^3 + \gamma^3\alpha^3 = 112\) find a cubic equation whose roots are \(\alpha^3\), \(\beta^3\) and \(\gamma^3\). [4]

In this question you must show detailed reasoning.
The equation $x^3 + 3x^2 - 2x + 4 = 0$ has roots $\alpha$, $\beta$ and $\gamma$.

\begin{enumerate}[label=(\roman*)]
\item Using the identity $\alpha^3 + \beta^3 + \gamma^3 = (\alpha + \beta + \gamma)^3 - 3(\alpha\beta + \beta\gamma + \gamma\alpha)(\alpha + \beta + \gamma) + 3\alpha\beta\gamma$ find the value of $\alpha^3 + \beta^3 + \gamma^3$. [3]

\item Given that $\alpha^3\beta^3 + \beta^3\gamma^3 + \gamma^3\alpha^3 = 112$ find a cubic equation whose roots are $\alpha^3$, $\beta^3$ and $\gamma^3$. [4]
\end{enumerate}

\hfill \mbox{\textit{SPS SPS ASFM Mechanics 2021 Q1 [7]}}