WJEC Further Unit 4 2024 June — Question 10 12 marks

Exam BoardWJEC
ModuleFurther Unit 4 (Further Unit 4)
Year2024
SessionJune
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSecond order differential equations
TypeParticular solution with initial conditions
DifficultyChallenging +1.3 This is a coupled differential equations problem requiring systematic elimination to derive a second-order ODE, then solving with initial conditions. While it involves multiple steps (differentiation, substitution, solving auxiliary equation, applying initial conditions), the techniques are standard for Further Maths and follow a predictable procedure without requiring novel insight. The algebra is moderately involved but routine for this level.
Spec4.10h Coupled systems: simultaneous first order DEs

The following simultaneous equations are to be solved. $$\frac{\mathrm{d}x}{\mathrm{d}t} = 4x + 2y + 6e^{3t}$$ $$\frac{\mathrm{d}y}{\mathrm{d}t} = 6x + 8y + 15e^{3t}$$
  1. Show that \(\frac{\mathrm{d}^2 x}{\mathrm{d}t^2} - 12\frac{\mathrm{d}x}{\mathrm{d}t} + 20x = 0\). [5]
  2. Given that \(\frac{\mathrm{d}x}{\mathrm{d}t} = 9\) and \(\frac{\mathrm{d}^2 x}{\mathrm{d}t^2} = 10\) when \(t = 0\), find the particular solution for \(x\) in terms of \(t\). [7]

Question 10:
AnswerMarks
1012
Total120
Types of room
AnswerMarks Guidance
HotelSingle Double
A12 30
B18 25
C19 50
Question
AnswerMarks
numberAdditional page, if required.
Write the question number(s) in the left-hand margin.
Question
AnswerMarks
numberAdditional page, if required.
Write the question number(s) in the left-hand margin.
Question 10:
10 | 12
Total | 120
Types of room
Hotel | Single | Double | Family | Total revenue
A | 12 | 30 | 8 | £2,668
B | 18 | 25 | 20 | £3,402
C | 19 | 50 | 16 | £4,581
Question
number | Additional page, if required.
Write the question number(s) in the left-hand margin.
Question
number | Additional page, if required.
Write the question number(s) in the left-hand margin.
The following simultaneous equations are to be solved.
$$\frac{\mathrm{d}x}{\mathrm{d}t} = 4x + 2y + 6e^{3t}$$
$$\frac{\mathrm{d}y}{\mathrm{d}t} = 6x + 8y + 15e^{3t}$$

\begin{enumerate}[label=(\alph*)]
\item Show that $\frac{\mathrm{d}^2 x}{\mathrm{d}t^2} - 12\frac{\mathrm{d}x}{\mathrm{d}t} + 20x = 0$. [5]

\item Given that $\frac{\mathrm{d}x}{\mathrm{d}t} = 9$ and $\frac{\mathrm{d}^2 x}{\mathrm{d}t^2} = 10$ when $t = 0$, find the particular solution for $x$ in terms of $t$. [7]
\end{enumerate}

\hfill \mbox{\textit{WJEC Further Unit 4 2024 Q10 [12]}}