WJEC Further Unit 4 2024 June — Question 9 9 marks

Exam BoardWJEC
ModuleFurther Unit 4 (Further Unit 4)
Year2024
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard trigonometric equations
TypeGeneral solution — find all solutions
DifficultyChallenging +1.8 This is a Further Maths trigonometric equation requiring multiple identities (double/triple angle formulas, sin 6θ expansion) and systematic algebraic manipulation to reduce to a solvable form. While the techniques are standard for Further Maths students, the multi-step nature, need to recognize which identities to apply, and careful algebraic handling across 9 marks places this well above average difficulty but not at the extreme end of Further Maths questions.
Spec1.05l Double angle formulae: and compound angle formulae1.05o Trigonometric equations: solve in given intervals

Find the general solution of the equation $$\sin 6\theta + 2\cos^2\theta = 3\cos 2\theta - \sin 2\theta + 1.$$ [9]

Question 9:
AnswerMarks
99
Question 9:
9 | 9
Find the general solution of the equation
$$\sin 6\theta + 2\cos^2\theta = 3\cos 2\theta - \sin 2\theta + 1.$$ [9]

\hfill \mbox{\textit{WJEC Further Unit 4 2024 Q9 [9]}}