| Exam Board | WJEC |
|---|---|
| Module | Unit 3 (Unit 3) |
| Year | 2018 |
| Session | June |
| Marks | 5 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Arithmetic Sequences and Series |
| Type | Find term or common difference |
| Difficulty | Moderate -0.3 This is a straightforward application of arithmetic progression formulas. Given n=7, the last term a+6d=71, and sum S_7=329, students can use S_n=n/2(first+last) to find the first term immediately (329=7/2(a+71) gives a=23), then solve for d. The question requires only direct formula application with no conceptual challenges or problem-solving insight. |
| Spec | 1.04h Arithmetic sequences: nth term and sum formulae |
Find seven numbers which are in arithmetic progression such that the last term is 71 and the sum of all of the numbers is 329. [5]
\hfill \mbox{\textit{WJEC Unit 3 2018 Q8 [5]}}