WJEC Unit 3 2018 June — Question 5 8 marks

Exam BoardWJEC
ModuleUnit 3 (Unit 3)
Year2018
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPartial Fractions
TypeRepeated linear factor with distinct linear factor – decompose and integrate
DifficultyModerate -0.3 This is a standard partial fractions question with a repeated linear factor, followed by routine integration using logarithms and the standard result for 1/(x-a)². The algebraic manipulation is straightforward, and the integration technique is directly taught. It's slightly easier than average because it follows a well-practiced procedure with no conceptual surprises, though the repeated factor adds minor complexity.
Spec1.02y Partial fractions: decompose rational functions1.08j Integration using partial fractions

  1. Show that $$\frac{3x}{(x-1)(x-4)^2} = \frac{A}{(x-1)} + \frac{B}{(x-4)} + \frac{C}{(x-4)^2},$$ where \(A\), \(B\) and \(C\) are constants to be found. [3]
  2. Evaluate \(\int_5^7 \frac{3x}{(x-1)(x-4)^2} \, dx\), giving your answer correct to 3 decimal places. [5]

\begin{enumerate}[label=(\alph*)]
\item Show that
$$\frac{3x}{(x-1)(x-4)^2} = \frac{A}{(x-1)} + \frac{B}{(x-4)} + \frac{C}{(x-4)^2},$$
where $A$, $B$ and $C$ are constants to be found. [3]

\item Evaluate $\int_5^7 \frac{3x}{(x-1)(x-4)^2} \, dx$, giving your answer correct to 3 decimal places. [5]
\end{enumerate}

\hfill \mbox{\textit{WJEC Unit 3 2018 Q5 [8]}}