| Exam Board | WJEC |
|---|---|
| Module | Unit 2 (Unit 2) |
| Year | 2018 |
| Session | June |
| Marks | 7 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Forces, equilibrium and resultants |
| Type | Lift with occupant problems |
| Difficulty | Moderate -0.8 This is a straightforward mechanics problem requiring application of Newton's second law to two connected bodies. Part (a) involves a single F=ma calculation with total mass, part (b) is immediate interpretation, and part (c) applies F=ma again to the person alone. All steps are routine with no conceptual subtlety—easier than average A-level questions which typically require more problem-solving or integration of multiple techniques. |
| Spec | 3.03c Newton's second law: F=ma one dimension3.03d Newton's second law: 2D vectors3.03f Weight: W=mg |
A person, of mass 68 kg, stands in a lift which is moving upwards with constant acceleration. The lift is of mass 770 kg and the tension in the lift cable is 8000 N.
\begin{enumerate}[label=(\alph*)]
\item Determine the acceleration of the lift, giving your answer correct to two decimal places. [3]
\item State whether the lift is getting faster, staying at the same speed or slowing down. [1]
\item Calculate the magnitude of the reaction of the floor of the lift on the person. [3]
\end{enumerate}
\hfill \mbox{\textit{WJEC Unit 2 2018 Q10 [7]}}