WJEC Unit 1 2024 June — Question 1 4 marks

Exam BoardWJEC
ModuleUnit 1 (Unit 1)
Year2024
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicChain Rule
TypeFind gradient at specific point
DifficultyModerate -0.8 This is a straightforward differentiation question requiring only basic power rule application after rewriting terms in index form (x^{1/2} and x^{-1}), then substituting x=9. It's simpler than average A-level questions as it involves no problem-solving, just routine technique with a single substitution step.
Spec1.07i Differentiate x^n: for rational n and sums

Given that \(y = 12\sqrt{x} - \frac{27}{x} + 4\), find the value of \(\frac{dy}{dx}\) when \(x = 9\). [4]

Question 1:
AnswerMarks
14
Question 1:
1 | 4
Given that $y = 12\sqrt{x} - \frac{27}{x} + 4$, find the value of $\frac{dy}{dx}$ when $x = 9$. [4]

\hfill \mbox{\textit{WJEC Unit 1 2024 Q1 [4]}}