| Exam Board | OCR MEI |
|---|---|
| Module | Further Mechanics Major (Further Mechanics Major) |
| Session | Specimen |
| Marks | 5 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Hooke's law and elastic energy |
| Type | Particle attached to two separate elastic strings |
| Difficulty | Standard +0.3 This is a straightforward equilibrium problem with elastic strings. Part (i) requires direct application of Hooke's law (T = λx/l), which is routine recall. Part (ii) involves resolving forces vertically and horizontally using basic trigonometry from the geometry, then solving for M. While it requires multiple steps and careful geometry, the techniques are standard for Further Mechanics with no novel insight needed. Slightly easier than average due to the structured approach and familiar context. |
| Spec | 3.03n Equilibrium in 2D: particle under forces6.02g Hooke's law: T = k*x or T = lambda*x/l6.02h Elastic PE: 1/2 k x^2 |
| Answer | Marks | Guidance |
|---|---|---|
| 3 | (i) | (cid:79)e 29.4(cid:117)0.3 |
| Answer | Marks |
|---|---|
| Tension is 12.6N | M1 |
| Answer | Marks |
|---|---|
| [2] | 3.4 |
| Answer | Marks |
|---|---|
| 1.1 | M |
| Answer | Marks | Guidance |
|---|---|---|
| 3 | (ii) | Let (cid:84)be angle between each string and |
| Answer | Marks |
|---|---|
| =1.54 | M1 |
| Answer | Marks |
|---|---|
| [3] | C |
| Answer | Marks |
|---|---|
| 1.1 | Resolve vertically |
Question 3:
3 | (i) | (cid:79)e 29.4(cid:117)0.3
Use Hooke's law: T (cid:32) (cid:32) (cid:32)12.6
l 0.7
Tension is 12.6N | M1
A1
[2] | 3.4
I
1.1 | M
Use of Hooke's law
Correct answer
3 | (ii) | Let (cid:84)be angle between each string and
vertical, then 2Tcos(cid:84)(cid:32)Mg
2(cid:117)12.6(cid:117)0.6
M (cid:32) P
9.8
=1.54 | M1
E
M1
A1
[3] | C
3.4
1.1a
1.1 | Resolve vertically
SubstitutionThe fixed points E and F are on the same horizontal level with EF = 1.6 m. A light string has natural length 0.7 m and modulus of elasticity 29.4 N. One end of the string is attached to E and the other end is attached to a particle of mass $M$ kg. A second string, identical to the first, has one end attached to F and the other end attached to the particle. The system is in equilibrium in a vertical plane with each string stretched to a length of 1 m, as shown in Fig. 3.
\includegraphics{figure_3}
\begin{enumerate}[label=(\roman*)]
\item Find the tension in each string. [2]
\item Find $M$. [3]
\end{enumerate}
\hfill \mbox{\textit{OCR MEI Further Mechanics Major Q3 [5]}}