OCR Further Statistics 2020 November — Question 4 7 marks

Exam BoardOCR
ModuleFurther Statistics (Further Statistics)
Year2020
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicUniform Distribution
TypeFind parameter from variance or other constraint
DifficultyStandard +0.8 This question requires understanding of discrete uniform distributions, applying linearity of expectation and variance scaling properties, then solving simultaneous equations involving the formulas for mean and variance of consecutive integers. While the concepts are standard Further Maths material, the algebraic manipulation and systematic approach needed across multiple steps makes it moderately challenging, above average difficulty but not requiring deep insight.
Spec5.02c Linear coding: effects on mean and variance5.02e Discrete uniform distribution

The random variable \(X\) is equally likely to take any of the \(n\) integer values from \(m + 1\) to \(m + n\) inclusive. It is given that \(\text{E}(3X) = 30\) and \(\text{Var}(3X) = 36\). Determine the value of \(m\) and the value of \(n\). [7]

Question 4:
AnswerMarks
43E(X) = 30 or E(X) = 10
9×Var(X) = 36 or Var(X) = 4
1 (n2 −1)=4
12
⇒ n = 7
E(X – m) = 1(n+1)
AnswerMarks
2B1
B1
M1
A1
AnswerMarks
M12.2a
2.2a
1.1
2.2a
AnswerMarks
3.1bUsed, stated or implied
One of these, used, stated or implied
Use variance of uniform
n = 7 only, no need for “reject –7”
Use expectation of uniform, e.g.
AnswerMarks
2m + n + 1 = 20.Allow if E(3X + m) used
rather than E[3(X + m )]
AnswerMarks
OR:Var(Y + m) = 1 (n2−1)
12M1
A1
AnswerMarks
M11.1
2.2a
3.1b
n = 7 only, no need for “reject –7”
⇒ n = 7
Use expectation of uniform, e.g.
E(Y + m) = ½(n + 1) + m
2m + n + 1 = 20.
10 – m = 4
AnswerMarks
m = 6M1
A1
AnswerMarks
[7]2.1
2.2aValidly derive single equation for m
m = 6 onlyNB: Var = (n – 1)2/12 is
from continuous uniform!
M1
A1
M1
1.1
2.2a
3.1b
AnswerMarks Guidance
QuestionAnswer Marks
Question 4:
4 | 3E(X) = 30 or E(X) = 10
9×Var(X) = 36 or Var(X) = 4
1 (n2 −1)=4
12
⇒ n = 7
E(X – m) = 1(n+1)
2 | B1
B1
M1
A1
M1 | 2.2a
2.2a
1.1
2.2a
3.1b | Used, stated or implied
One of these, used, stated or implied
Use variance of uniform
n = 7 only, no need for “reject –7”
Use expectation of uniform, e.g.
2m + n + 1 = 20. | Allow if E(3X + m) used
rather than E[3(X + m )]
OR: | Var(Y + m) = 1 (n2−1)
12 | M1
A1
M1 | 1.1
2.2a
3.1b
n = 7 only, no need for “reject –7”
⇒ n = 7
Use expectation of uniform, e.g.
E(Y + m) = ½(n + 1) + m
2m + n + 1 = 20.
10 – m = 4
m = 6 | M1
A1
[7] | 2.1
2.2a | Validly derive single equation for m
m = 6 only | NB: Var = (n – 1)2/12 is
from continuous uniform!
M1
A1
M1
1.1
2.2a
3.1b
Question | Answer | Marks | AO | Guidance
The random variable $X$ is equally likely to take any of the $n$ integer values from $m + 1$ to $m + n$ inclusive. It is given that $\text{E}(3X) = 30$ and $\text{Var}(3X) = 36$.

Determine the value of $m$ and the value of $n$. [7]

\hfill \mbox{\textit{OCR Further Statistics 2020 Q4 [7]}}