CAIE P1 2010 June — Question 7 8 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2010
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPolar coordinates
TypeMetal plate perimeter and area
DifficultyStandard +0.3 This is a straightforward application of circle geometry and radians. Part (i) uses inverse trig (arcsin) with a given answer to verify, parts (ii) and (iii) require standard arc length and sector area formulas. The symmetry simplifies calculations, and all techniques are routine for A-level Pure Maths, making it slightly easier than average.
Spec1.05d Radians: arc length s=r*theta and sector area A=1/2 r^2 theta

7 \includegraphics[max width=\textwidth, alt={}, center]{71fe6352-e0dc-4c3a-8b54-99709a1782ca-3_744_675_255_735} The diagram shows a metal plate \(A B C D E F\) which has been made by removing the two shaded regions from a circle of radius 10 cm and centre \(O\). The parallel edges \(A B\) and \(E D\) are both of length 12 cm .
  1. Show that angle \(D O E\) is 1.287 radians, correct to 4 significant figures.
  2. Find the perimeter of the metal plate.
  3. Find the area of the metal plate.

AnswerMarks Guidance
(i) \(\sin \frac{1}{2}\theta = \frac{6}{10}\)M1 Use of trig with/without radians
Angle \(DOE = 1.287\) radians.A1 co – answer given.
[2]
(ii) \(P = 12 + 12 + 2 × 10 ×\) angle \(BOD\)M1 Use of \(s = r\theta\) for arc length.
Angle \(BOD = (\pi - 1.287)\)M1 Correct angle
\(\to 61.1\)A1 co
[3]
(iii) Sector \(DOE = \frac{1}{2} × 10^2 × 1.287\)M1 Correct formula used with radians.
Triangle \(DOE = \frac{1}{2} × 10^2 × \sin 1.287\)M1 Correct formula used with radians.
Area \(= \pi × 10^2 - (2\) sectors \(- 2\) triangles) (or \(48 + 48 + 2×\frac{1}{2}×10^2×(\pi - 1.287)\))M1 M1
\(\to 281\) or \(282\)A1 co
[3]
(i) $\sin \frac{1}{2}\theta = \frac{6}{10}$ | M1 | Use of trig with/without radians
Angle $DOE = 1.287$ radians. | A1 | co – answer given.
 | [2] |

(ii) $P = 12 + 12 + 2 × 10 ×$ angle $BOD$ | M1 | Use of $s = r\theta$ for arc length.
Angle $BOD = (\pi - 1.287)$ | M1 | Correct angle
$\to 61.1$ | A1 | co
 | [3] |

(iii) Sector $DOE = \frac{1}{2} × 10^2 × 1.287$ | M1 | Correct formula used with radians.
Triangle $DOE = \frac{1}{2} × 10^2 × \sin 1.287$ | M1 | Correct formula used with radians.
Area $= \pi × 10^2 - (2$ sectors $- 2$ triangles) (or $48 + 48 + 2×\frac{1}{2}×10^2×(\pi - 1.287)$) | M1 | M1 |
$\to 281$ or $282$ | A1 | co
 | [3] |

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7\\
\includegraphics[max width=\textwidth, alt={}, center]{71fe6352-e0dc-4c3a-8b54-99709a1782ca-3_744_675_255_735}

The diagram shows a metal plate $A B C D E F$ which has been made by removing the two shaded regions from a circle of radius 10 cm and centre $O$. The parallel edges $A B$ and $E D$ are both of length 12 cm .\\
(i) Show that angle $D O E$ is 1.287 radians, correct to 4 significant figures.\\
(ii) Find the perimeter of the metal plate.\\
(iii) Find the area of the metal plate.

\hfill \mbox{\textit{CAIE P1 2010 Q7 [8]}}