CAIE P1 2010 June — Question 2 5 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2010
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Theorem (positive integer n)
TypeProduct with reciprocal term binomial
DifficultyModerate -0.8 This is a straightforward binomial expansion question requiring routine application of the binomial theorem with a reciprocal term. Part (i) involves direct calculation of three terms using the formula, and part (ii) requires identifying which terms from part (i) contribute to x^4 after multiplication—a standard technique. The question is easier than average as it involves no problem-solving insight, just methodical application of a well-practiced procedure.
Spec1.04a Binomial expansion: (a+b)^n for positive integer n

2
  1. Find the first three terms, in descending powers of \(x\), in the expansion of \(\left( x - \frac { 2 } { x } \right) ^ { 6 }\).
  2. Find the coefficient of \(x ^ { 4 }\) in the expansion of \(\left( 1 + x ^ { 2 } \right) \left( x - \frac { 2 } { x } \right) ^ { 6 }\).

AnswerMarks Guidance
(i) \(\left(x - \frac{2}{x}\right)^6 = x^6 - 12x^4 + 60x^2\)B1 ×3 co
[3]
(ii) \(\times (1 + x^2) \to 60 - 12 = 48\)M1 A1√ Must be exactly 2 terms. √ from his (i).
[2]
(i) $\left(x - \frac{2}{x}\right)^6 = x^6 - 12x^4 + 60x^2$ | B1 ×3 | co
 | [3] |

(ii) $\times (1 + x^2) \to 60 - 12 = 48$ | M1 A1√ | Must be exactly 2 terms. √ from his (i).
 | [2] |

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2 (i) Find the first three terms, in descending powers of $x$, in the expansion of $\left( x - \frac { 2 } { x } \right) ^ { 6 }$.\\
(ii) Find the coefficient of $x ^ { 4 }$ in the expansion of $\left( 1 + x ^ { 2 } \right) \left( x - \frac { 2 } { x } \right) ^ { 6 }$.

\hfill \mbox{\textit{CAIE P1 2010 Q2 [5]}}