AQA Further Paper 2 2023 June — Question 4 1 marks

Exam BoardAQA
ModuleFurther Paper 2 (Further Paper 2)
Year2023
SessionJune
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHyperbolic functions
TypeSketch graphs of hyperbolic functions
DifficultyEasy -1.2 This is a straightforward recall question testing knowledge that cosh^{-1}(y) requires y ≥ 1. Students simply need to solve x - 3 ≥ 1 to get x ≥ 4, then select from given options. No problem-solving or multi-step reasoning required, just direct application of a standard domain restriction.
Spec4.07f Inverse hyperbolic: logarithmic forms

It is given that \(f(x) = \cosh^{-1}(x - 3)\) Which of the sets listed below is the greatest possible domain of the function \(f\)? Circle your answer. [1 mark] \(\{x : x \geq 4\}\) \quad \(\{x : x \geq 3\}\) \quad \(\{x : x \geq 1\}\) \quad \(\{x : x \geq 0\}\)

Question 4:
AnswerMarks Guidance
4Circles correct answer 2.2a
Question total1
QMarking Instructions AO
Question 4:
4 | Circles correct answer | 2.2a | B1 | { x:x≥4 }
Question total | 1
Q | Marking Instructions | AO | Marks | Typical solution
It is given that $f(x) = \cosh^{-1}(x - 3)$

Which of the sets listed below is the greatest possible domain of the function $f$?

Circle your answer.
[1 mark]

$\{x : x \geq 4\}$ \quad $\{x : x \geq 3\}$ \quad $\{x : x \geq 1\}$ \quad $\{x : x \geq 0\}$

\hfill \mbox{\textit{AQA Further Paper 2 2023 Q4 [1]}}