AQA Further Paper 1 2019 June — Question 3 1 marks

Exam BoardAQA
ModuleFurther Paper 1 (Further Paper 1)
Year2019
SessionJune
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIntegration with Partial Fractions
DifficultyModerate -0.8 This is a straightforward application of the mean value formula for a function: integrate f(x) over the interval and divide by the interval length. The integration of x² - 1 is elementary, and the arithmetic is simple. Being worth only 1 mark with multiple choice answers confirms it's a routine calculation requiring no problem-solving or insight, making it easier than average.
Spec4.08e Mean value of function: using integral

The function \(f(x) = x^2 - 1\) Find the mean value of \(f(x)\) from \(x = -0.5\) to \(x = 1.7\) Give your answer to three significant figures. Circle your answer. [1 mark] \(-0.521\) \quad \(-0.434\) \quad \(-0.237\) \quad \(0.786\)

Question 3:
AnswerMarks Guidance
3Circles correct answer AO1.1b
Total1
QMarking Instructions AO
Question 3:
3 | Circles correct answer | AO1.1b | B1 | −0.237
Total | 1
Q | Marking Instructions | AO | Marks | Typical Solution
The function $f(x) = x^2 - 1$

Find the mean value of $f(x)$ from $x = -0.5$ to $x = 1.7$

Give your answer to three significant figures.

Circle your answer.
[1 mark]

$-0.521$ \quad $-0.434$ \quad $-0.237$ \quad $0.786$

\hfill \mbox{\textit{AQA Further Paper 1 2019 Q3 [1]}}