Easy -1.2 This is a direct application of the elastic potential energy formula EPE = λx²/(2l) with all values given explicitly. It requires only substitution into a standard formula with no problem-solving, making it easier than average even for Further Maths, though the multiple-choice format and 1-mark allocation confirm it's a routine recall question.
An elastic string has modulus of elasticity 20 newtons and natural length 2 metres.
The string is stretched so that its extension is 0.5 metres.
Find the elastic potential energy stored in the string.
Circle your answer.
1.25 J \quad\quad 5.5 J \quad\quad 5 J \quad\quad 10 J
[1 mark]
An elastic string has modulus of elasticity 20 newtons and natural length 2 metres.
The string is stretched so that its extension is 0.5 metres.
Find the elastic potential energy stored in the string.
Circle your answer.
1.25 J \quad\quad 5.5 J \quad\quad 5 J \quad\quad 10 J
[1 mark]
\hfill \mbox{\textit{AQA Further AS Paper 2 Mechanics 2024 Q1 [1]}}