AQA Further AS Paper 2 Mechanics 2021 June — Question 1 1 marks

Exam BoardAQA
ModuleFurther AS Paper 2 Mechanics (Further AS Paper 2 Mechanics)
Year2021
SessionJune
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHooke's law and elastic energy
TypeElastic potential energy calculations
DifficultyEasy -1.8 This is a direct one-step application of Hooke's Law (F = kx) requiring only substitution: 20 = k(0.6-0.4), so k = 100. It's a 1-mark multiple choice question testing basic recall with no problem-solving element, making it significantly easier than average A-level questions.
Spec6.02g Hooke's law: T = k*x or T = lambda*x/l

A light spring of natural length 0.6 metres is compressed to a length of 0.4 metres by a force of 20 newtons. The stiffness of the spring is \(k\) N m\(^{-1}\) Find \(k\) Circle your answer. [1 mark] 20 50 100 200

Question 1:
AnswerMarks Guidance
1Circles correct answer 1.1b
Total1
QMarking instructions AO
Question 1:
1 | Circles correct answer | 1.1b | B1 | 100
Total | 1
Q | Marking instructions | AO | Marks | Typical solution
A light spring of natural length 0.6 metres is compressed to a length of 0.4 metres by a force of 20 newtons.

The stiffness of the spring is $k$ N m$^{-1}$

Find $k$

Circle your answer.
[1 mark]

20        50        100        200

\hfill \mbox{\textit{AQA Further AS Paper 2 Mechanics 2021 Q1 [1]}}